Page 297 - Solutions Manual to accompany Electric Machinery Fundamentals
P. 297
(e) The real and reactive power supplied by the generator when the switch is closed is just the sum of
the real and reactive powers of Loads 1, 2, and 3. The powers of Loads 1 and 2 have already been
calculated. The real and reactive power of Load 3 are:
P 80 kW
3
Q P tan P tan cos PF 80 kW tan 31.79 49.6 kvar
1
3
P P P P 100 kW 64 kW 80 kW 244 kW
G 1 2 3
Q G Q 1 Q 2 Q 3 48.4 kvar 48 kvar 49.6 kvar 46.8 kvar
P Q
(f) The line current when the switch is closed is given by I , where tan 1 G .
L
3 V cos P
L G
Q 46.8 kvar
tan 1 G tan 1 10.86
P G 244 kW
P 244 kW
I 298.8 A
L
3 V L cos V cos 10.86
3 480
(g) The total line current from the generator is 298.8 A. The line currents to each individual load are:
P 100 kW
I 1 133.6 A
1
L
3 V L cos 1 3 480 V 0.9
S 80 kVA
I 2 96.2 A
L
2
3 V L 3 V 480
P 80 kW
I L 3 3 113.2 A
3 V L cos 3 3 480 V 0.85
The sum of the three individual line currents is 343 A, while the current supplied by the generator is 298.8
A. These values are not the same, because the three loads have different impedance angles. Essentially,
Load 3 is supplying some of the reactive power being consumed by Loads 1 and 2, so that it does not
have to come from the generator.
A-4. Prove that the line voltage of a Y-connected generator with an acb phase sequence lags the corresponding
phase voltage by 30. Draw a phasor diagram showing the phase and line voltages for this generator.
SOLUTION If the generator has an acb phase sequence, then the three phase voltages will be
V V 0
an
V V 240
bn
V V 120
cn
The relationship between line voltage and phase voltage is derived below. By Kirchhoff’s voltage law,
the line-to-line voltage V ab is given by
V V V
ab a b
V V 0 V 240
ab
1 3 3 3
V V V j V V j V
ab
2 2 2 2
3 1
V 3V j
ab
2 2
V 3V 30
ab
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