Page 58 - Solutions Manual to accompany Electric Machinery Fundamentals

The resulting plot is shown below:

(e) The base phase voltage on the primary side is given by:
V 14.4 kV
V  P ,base  LP   8.314 kV
3 3
The base impedance on the primary side is given by

 V 2 8.314 kV 2
Z     .base,S  230 
base,S
S  ,base 300 kVA
The per-phase impedance on the primary side is
R EQ  18.94 
X EQ  35.77 

The per-unit impedance is
R 18.94 
R  EQ   0.082 pu
EQ,pu
Z 230 
base
X 35.77 
X  EQ   0.156 pu
EQ,pu
Z 230 
base
The excitation branch information was not given for the transformer, so the per-unit, per-phase equivalent
circuit of the transformer bank is shown below:

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