Page 88 - Intro to Tensor Calculus
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               Epsilon Permutation Symbol

                   Associated with the e−permutation symbols there are the epsilon permutation symbols defined by the
               relations
                                                  √                 ijk   1  ijk
                                               ijk =  ge ijk  and      = √ e                          (1.3.30)
                                                                           g
               where g is the determinant of the metrices g ij .
                   It can be demonstrated that the e ijk permutation symbol is a relative tensor of weight −1 whereas the
                 ijk permutation symbol is an absolute tensor. Similarly, the e ijk  permutation symbol is a relative tensor of
               weight +1 and the corresponding   ijk  permutation symbol is an absolute tensor.
               EXAMPLE 1.3-10. (  permutation symbol)
                   Show that e ijk is a relative tensor of weight −1 and the corresponding   ijk permutation symbol is an
               absolute tensor.
               Solution: Examine the Jacobian                 1    1    1
                                                             ∂x  ∂x   ∂x
                                                                        3
                                                     x        2    2    2
                                                             ∂x 1  ∂x 2  ∂x
                                                  J      =      ∂x 1  ∂x 2  ∂x 3
                                                     x       ∂x 3  ∂x 3  ∂x
                                                                        3
                                                             ∂x  ∂x   ∂x
                                                            ∂x 1  ∂x 2  ∂x 3
               and make the substitution
                                                         ∂x i
                                                     i
                                                    a =    j  ,i, j =1, 2, 3.
                                                     j
                                                         ∂x
               From the definition of a determinant we may write
                                                                  x
                                                            k
                                                        i
                                                          j
                                                   e ijk a a a = J( )e mnp .                          (1.3.31)
                                                        m n p
                                                                  x
               By definition, e mnp = e mnp in all coordinate systems and hence equation (1.3.31) can be expressed in the
               form
                                                  x        ∂x ∂x ∂x
                                               h    i −1      i   j  k
                                                J( )    e ijk  m  n   p  = e mnp                      (1.3.32)
                                                  x        ∂x ∂x ∂x
               which demonstrates that e ijk transforms as a relative tensor of weight −1.
                   We have previously shown the metric tensor g ij is a second order covariant tensor and transforms
                                             m
                                           ∂x ∂x  n
               according to the rule g ij  = g mn  . Taking the determinant of this result we find
                                              i
                                           ∂x ∂x  j
                                                                m 2    h     i 2

                                                               ∂x         x
                                              g = |g | = |g mn|        = g J( )                       (1.3.33)
                                                   ij
                                                              ∂x i        x

               where g is the determinant of (g ij )and g is the determinant of (g ). This result demonstrates that g is a
                                                                          ij
               scalar invariant of weight +2. Taking the square root of this result we find that
                                                        p    √    x
                                                         g =   gJ( ).                                 (1.3.34)
                                                                  x
                                   √
               Consequently, we call  g a scalar invariant of weight +1. Now multiply both sides of equation (1.3.32) by
               √
                 g and use (1.3.34) to verify the relation
                                                         i
                                                             j
                                                √      ∂x ∂x ∂x  k   p
                                                 ge ijk  m   n   p  =  g e mnp .                      (1.3.35)
                                                      ∂x ∂x ∂x
                                                              √
               This equation demonstrates that the quantity   ijk =  ge ijk transforms like an absolute tensor.
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