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3. The Heat Equation
        94
                     1.2
                     0.8
                                  −−−: N=10
                     0.6
                                  ___: N=100
                     0.4
                     0.2 1        −.−: N=3
                      0
                      0   0.1  0.2  0.3  0.4  0.5  0.6  0.7  0.8  0.9  1
        FIGURE 3.3. The first 3, 10, and 100 terms of the sine-series approximation of
        f(x)=1.
          When allowing infinite series in the initial data, the solution given by
        (3.22) also becomes an infinite series. For the present example, we get the
        following formal solution:
                           ∞
                        4       1   −((2k−1)π) t
                                            2
                u(x, t)=           e          sin ((2k − 1)πx).     (3.24)
                        π    2k − 1
                          k=1
        Recall here that this solution is referred to as being formal since we have
        not proved that the series and its derivatives converge and satisfy all the
        requirements of the heat equation (3.20).
          We have plotted the formal solution of this problem as a function of x
        at t =0, 0.01, 0.1 in Fig. 3.4. Note that the observations concerning the
        qualitative behavior of the solution stated in Example 3.1 also apply to the
        present solution.


          The key observation of the example above is that finite linear combi-
        nations of eigenfunctions are not sufficient to cover all interesting initial
        functions f(x). Thus we are led to allow infinite linear combinations of the
        form
                                      ∞

                               f(x)=    c k sin (kπx).              (3.25)
                                     k=1
        By letting N tend to infinity in (3.22), we obtain the corresponding formal
        solution of the problem (3.20),
                                   ∞
                                             2
                                        −(kπ) t
                          u(x, t)=    c k e    sin (kπx).           (3.26)
                                  k=1
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