Page 187 - Introduction to Information Optics
P. 187

172                    3. Communication with Optics

          The constants K and y can be found by using the following boundary
       condition between the core and the cladding surfaces. Mathematically, it can
       be expressed as


                                                                      (3.26)
                                 p          op

       Substituting Eq. (3.25) into Eq. (3.26), we obtain
                              A-J m(Ka)=C-K m(ya\                   (3.27«)
                            A-K-J m(Ka] =C-yKUy fl ),                (3.27J»)

       where symbol prime indicates differentiation with respect to the argument.
       Dividing Eq. (3.27a) by Eq. (3.Tib), we get following formular (so-called
       dispersion relationship):

                                J m(Kd)    K m(ya)
                                                                     (.5.25)
                               K • J' m(Ka]  y • K' m(ya)
       To understand Eq. (3.28), let us substitute Eq. (3.20) into Eq. (3.28). Then, Eq.
       (3.28) becomes


                                   2
                      • J' m(Jn\kl - ft  a)
       Equation (3.29) determines the possible values of propagation constant ft, as
       discussed in the following:
                          lftz
          1. Since the term e  represents the light propagation in z direction, the ft
            is called the propagation constant. For nonattenuation propagation, ft
            must be a real number. For simplicity, assume that the light only
            propagates in one direction and ft must be larger than zero for the
            selected propagation directions (i.e., ft > 0).
                           2           2
          2. The conditions K  = n^k^ — ft  > 0 and /? > 0 result in ft < n^. The
                         2
                              2
            conditions of y  — ft  — n\k^ > 0 and /i > 0 result in /? > n 2k 0. Thus, the
            overall constraint on ft is
                                 n 2k 0<ft<n lk 0.                   (3.30)

          3. Multiplying l/k Q on both sides of Eq. (3.30), we get


                                   n 2<-<n l.                        (3,3 J)
   182   183   184   185   186   187   188   189   190   191   192