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1.4. Band-limited Analysis              23

       1.4.1. DEGREES OF FREEDOM

          Let f(t) be a band-limited signal the spectrum of which extends from zero
       frequency to a definite limit of v m. Assume that f(t) extends over a time interval
       of T, where v mT » 1. Strictly speaking, a band-limited signal cannot be time
       limited or vice versa. Now a question arises: How many sampling points (i.e.,
       degrees of freedom) are required to describe the function /(r), over T,
       uniquely? To answer this fundamental question we present an example.
          First, we let f(t) repeat itself at every time interval of T; that is,

                                  f(t) = f(t + T).

       Thus, the function f(t) over the period T, can be expanded in a Fourier series:
                                    M
                            fit) - X C»QXp(i2nnv 0t),                 (1.81)
                                  n- -M
       where v 0 = 1/T, and M — v mT.
          From this Fourier expansion, we see that f(t) contains a finite number of
       terms:

                              N = 2M + 1 =2v m T+ 1,
       which includes the zero-frequency Fourier coefficient C 0. If the duration T is
       sufficiently large, we see that the number of degree of freedom reduces to

                                    N*2v mT.                         (1.82)

       In other words, it requires a total of N equidistant sampling points of f(t\ over
       T, to describe the function
                                       T    1
                                   '• = * = *r-

       where t s is known as the Nyquist sampling interval and the corresponding
       sampling frequency is

                                   /, = 7 = 2v M,                    (1.84)
                                       s
       which is known as the Nyquist sampling rate or sampling frequency. Thus, we
       see that

                                     ,/>2v m.                        (1.85)
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