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428                                                   Part IV Siructural Reliability


                          assumed to follow normal probability distribution with mean value ps=20,000 ft-ton
                          and pz=30,000 ft-ton, respectively, and standard deviations of 0~=2,500 ft-ton and
                          0~=3,000 ft-ton, respectively. What is failure probability for the hull?
                  Solution
                          The reliability index, p, may be estimated using Cornel1 safety index method




                          Substituting in the numerical values for p~, ps, OR and (SS,  we may get

                              30000 - 20000  = 2.56
                          P=
                             J2500’  +30002
                          The corresponding failure probability is
                          Pf =  5.23YE-3



















                                                         Random variable

                             Figure 23.6  Load and Strength Probability Density hnctions

                  23.11.2  Example 23.2: p Safety Index Method
                  Problem
                          Assuming the random variables R and S are corresponding to the bending moments
                          of  a  ship  hull  girder  with  normal  distributions. The  mean  value  and  standard
                          deviations of R and S are p~=150, 0R=20 and ps=90, os=30 respectively. What is
                          the p index value and Pr using Hasofer Lind method?
                  Solution
                          The limit state function can be formed as
                          g(Z)=R-S
                          Based on Eqs. (23.12) and (23.13),  the random variables R and S can be expressed
                          using variables in standard normal space as
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