Page 165 - Marks Calculation for Machine Design
P. 165

P1: Rakesh
                          January 4, 2005
                                      14:16
        Brown.cls
                 Brown˙C03
                              U.S. Customary  ADVANCED LOADINGS   SI/Metric       147
                    Step 2. Using Eq. (3.31) calculate the maxi-  Step 2. Using Eq. (3.31) calculate the maxi-
                    mum pressure (p max ).             mum pressure (p max ).
                             2F                              2F
                       p max =                         p max =
                            πbL                              πbL
                             2(32,500 lb)  65,000 lb           2(147,500 N)  295,000 N
                          =            =                   =              =
                            π(0.11 in)(4in)  1.38 in 2       π(0.0028 m)(0.1m)  0.00088 m 2
                          = 47,025 lb/in 2                 = 335,400, 000 N/m 2
                          = 47.0 kpsi                      = 335.4MPa
                    Step 3. As Poisson’s ratio (ν) for the steel  Step 3. As Poisson’s ratio (ν) for the steel
                    wheels is close to the 0.3 used to graph the  wheels is close to the 0.3 used to graph the
                    principal stress equations in Fig. 3.12, assume  principal stress equations in Fig. 3.12, assume
                    the maximum shear stress occurs at 0.75b and  the maximum shear stress occurs at 0.75b and
                    is 0.3 p max . Therefore, using the value for the  is 0.3 p max . Therefore, using the value for the
                    maximum pressure found in Step 2, the maxi-  maximum pressure found in Step 2, the maxi-
                    mum shear stress (τ max ) is       mum shear stress (τ max ) is

                       τ max = 0.3p max = (0.3)(47.0 kpsi)  τ max = 0.3p max = (0.3)(335.4MPa)
                           = 14.1 kpsi                       = 100.6MPa

                    Step 4. Using Eq. (3.40), calculate the factor-  Step 4. Using Eq. (3.40), calculate the factor-
                    of-safety (n) for the design as    of-safety (n) for the design as
                       τ max  1                         τ max  1
                          =                                 =
                       S y   n                           S y  n
                        2                                2
                         1   14.1 kpsi  2 (14.1)          1   100.6MPa  2 (100.6)
                          =        =       = 0.47           =         =       = 0.48
                         n   60 kpsi   60                 n    420 MPa   420
                               2                                 2
                              1                                1
                         n =    = 2.13                     n =    = 2.09
                             0.47                             0.48
                    The design is safe by a factor of 2.  The design is safe by a factor of 2.




                    3.4 ROTATIONAL LOADING

                    Rotational loading occurs when a machine element, such as a flywheel, sawblade, or turbine
                    is spinning about a stationary axis at very high speed. Depending on the complexity of the
                    machine element, the stresses developed must be analyzed to determine if the design is
                    safe. It is appropriate here in Chap. 3 to limit the discussion to the basic rotating machine
                    element: the thin solid disk. Other types of rotating machine elements, such as flywheels,
                    will be discussed in a later chapter.
                      The geometry of a thin rotating disk is shown in Fig. 3.13,
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