Page 421 - Marks Calculation for Machine Design
P. 421

P1: Naresh
                          January 4, 2005
                                      15:28
        Brown.cls
                 Brown˙C09
                                             MACHINE ENERGY
                      For each spoke, the mass moment of inertia is given by Eq. (9.79)
                                                                                  403
                                                     1  2     2
                                       I spoke = m spoke  L spoke  + L cg       (9.79)
                                                    12
                    where the mass of each spoke (m spoke ) is given by Eq. (9.80).
                                                        1        2
                                                   2
                                    m spoke = ρπ L spoke r spoke  =  ρπ L spoke d spoke  (9.80)
                                                        4
                      Therefore, the total mass moment of inertia of the flywheel (I flywheel ) is
                                      I flywheel = I hub + I rim + N spokes I spoke  (9.81)
                    where (N spokes ) is the number of spokes.
                      Consider the following design option. In Example 1, the mass moment of inertia was
                    calculated for a thin solid circular disk. To improve the efficiency of this flywheel, a com-
                    posite design is considered. If the overall outside diameter remains the same, and using four
                    circular rods as spokes, compare the weight of a composite flywheel similar to Fig. 9.14
                    with the weight of a solid disk flywheel of equal mass moment of inertia.
                              U.S. Customary                      SI/Metric
                    Example 5. Compare the weight of a com-  Example 5. Compare the weight of a com-
                    posite flywheel design as shown in Fig. 9.14  posite flywheel design like shown in Fig. 9.14
                    with the thin, solid disk flywheel of Example 1,  with the thin solid disk flywheel of Example 1,
                    where                              where
                                                                       2
                                     2
                      I flywheel = 29.80 slug · ft (Example 1)  I flywheel = 39.85 kg · m (Example 1)
                                    3
                                                                       3
                         ρ = 15.2 slug/ft (steel)           ρ = 7,850 kg/m (steel)
                        D o = 3 ft (Example 1)             D o = 90 cm = 0.9 m (Example 1)
                         d o = 6in = 0.5 ft (hub)           d o = 16 cm = 0.16 m (hub)
                         d i = 3in = 0.25 ft (hub)          d i = 8cm = 0.08 m (hub)
                       w hub = 3in = 0.25 ft              w hub = 8cm = 0.08 m
                          t = 3in = 0.25 ft (rim)           t = 7cm = 0.07 m (rim)
                      L spoke = 12 in = 1ft              L spoke = 30 cm = 0.3 m
                       d spoke = 1.5 in = 0.125 ft       d spoke = 4cm = 0.04 m
                        L cg = 9in = 0.75 ft               L cg = 23 cm = 0.23 m
                    w rim is the only unknown dimension  w rim is the only unknown dimension
                    solution                           solution
                    Step 1. Calculate the weight of the thin solid  Step 1. Calculate the weight of the thin solid
                    disk flywheel in Example 1.         disk flywheel in Example 1.
                           W solid disk = m solid disk g      W solid disk = m solid disk g
                    where the mass of the solid disk is found by  where the mass of the solid disk is found by
                    multiplying density times its volume.  multiplying density times its volume.
                                1                                  1
                                                                        2
                                     2
                      m solid disk = ρ  πt d − d 2 i     m solid disk = ρ  πt d − d i 2
                                                                       o
                                     o
                                4                                  4

                                   volume                             volume

                                   slug  1                            kg  1
                            =  15.2     π(0.25 ft)             =  7,850    π(0.08 m)
                                   ft 3  4                            m 3  4
                                            2
                                                                        2
                                    2
                                                                                2
                              ×((3ft) − (0.25 ft) )              ×((0.9m) − (0.08 m) )
   416   417   418   419   420   421   422   423   424   425   426