Page 419 - Marks Calculation for Machine Design
P. 419

P1: Naresh
                          January 4, 2005
                                      15:28
        Brown.cls
                 Brown˙C09
                              U.S. Customary  MACHINE ENERGY      SI/Metric       401
                    Step 11. Calculate the slope (a) of the motor  Step 11. Calculate the slope (a) of the motor
                    curve in the linear region using Eq. (9.70) as  curve in the linear region using Eq. (9.70) as
                            T 1       15.2ft · lb             T 1       22.1N · m
                      a =       =                       a =        =
                         ω 1 − ω syn  (1,725 − 1,800) rpm   ω 1 − ω syn  (1,725 − 1,800) rpm
                         15.2 ft · lb    ft · lb            22.1 N · m     N · m
                       =         =−0.203                  =         =−0.295
                         −75 rpm         rpm                −75 rpm         rpm
                    Step 12. Using the slope (a) found in step 11,  Step 12. Using the slope (a) found in step 11,
                    the times (t 1 ) and (t 2 ), and the torques (T 1 ) and  the times (t 1 ) and (t 2 ), and the torques (T 1 ) and
                    (T 2 ) in Eq. (9.69), calculate the mass moment  (T 2 ) in Eq. (9.69), calculate the mass moment
                    of inertia of the system (I sys ) as  of inertia of the system (I sys ) as
                           a (t 2 − t 1 )                     a (t 2 − t 1 )
                       I sys =                           I sys =
                               T 2                                T 2
                            ln                                ln
                               T 1                                T 1

                                  ft · lb                            N · m
                            −0.203     (1 − 0.04) s            −0.295     (1 − 0.04) s
                                   rpm                               rpm
                         =                                  =
                             ln (1.5ft · lb/15.2ft · lb)       ln (2.25 N · m/22.1N · m)
                                      ft · lb · s                        N · m · s
                           (−0.203)(0.96)                     (−0.295)(0.96)
                                        rpm                               rpm
                         =                                  =
                                ln (0.099)                         ln (0.102)
                           −0.195 ft · lb · s                 −0.283 N · m · s
                         =                                  =
                             −2.316 rpm                        −2.285 rpm
                                ft · lb · s  1 rpm                N · m · s  1 rpm
                         = 0.084     ×                      = 0.124     ×
                                 rpm   2 π rad                      rpm   2 π rad
                                        60  s                             60  s
                                60                                 60
                                        2
                                                                           2
                         = (0.084)  (ft · lb · s )          = (0.124)  (N · m · s )
                                2 π                                2 π
                                 slug · ft                        kg · m

                         = 0.8  ft ·   · s 2                = 1.2     · m · s 2
                                   s 2                             s 2
                         = 0.8 slug · ft 2                  = 1.2kg · m 2
                     Remember that the mass moment of inertia  Remember that the mass moment of inertia
                    (I sys ) found in step 12 is for the entire system  (I sys ) found in step 12 is for the entire system
                    that includes the flywheel.         that includes the flywheel.
                    9.3.4 Composite Flywheels
                    The flywheel shown in Fig. 9.8 is the simplest of designs, that is, a solid circular disk. This
                    is probably the easiest and the most economical design to produce; however, it is not the
                    most efficient use of material, and therefore, weight. This has been known for quite some
                    time, as the design of more efficient flywheels became almost an art in the nineteenth
                    century, carrying on to the twentieth century and now to the new millennium.
                      Better designs are achieved by moving material from near the axis of rotation and placing
                    it as far as practical from the axis. (Remember, mass moment of inertia is a measure of the
                    distribution of mass, and mass farther away from the axis counts more than the same amount
                    of mass near the axis.) The traditional theme of more efficient flywheels is shown in Fig. 9.13,
   414   415   416   417   418   419   420   421   422   423   424