Page 608 - Mathematical Techniques of Fractional Order Systems
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578  Mathematical Techniques of Fractional Order Systems

                                  q
                                D z 2 5 ae 3 2 ae 2 1 de 1 1 u 2
               Here, e 3 5 α 2 , is the virtual controller
                                  q
                                D z 2 5 aα 2 2 az 2 1 dz 1 1 u 2     ð19:33Þ
               The new Lyapunov function for the above system can be written as,
                                               1
                                      V 2 5 V 1 1  z 2 2
                                               2
                                  q        2           q
                              .D V 2 #2 az 2 z 1 z 2 1 z 2 D z 2
                                           1
                                 2
                           #2 az 2 z 1 z 2 1 z 2 faα 2 2 az 2 1 dz 1 1 u 2 g
                                 1
               For α 2 5 0 and u 2 5 z 1 2 dz 1 ,
                                              2
                                     q
                                    D V 2 #2 az 2 az 2
                                              1    2
               The above expression satisfies the stability condition. Next, for
            z 3 5 e 3 2 α 2 ,
                            q
                           D z 3 5 ce 2 2 e 2 e 4 2 ~ x 4 e 2 2 e 4 ~ x 2 2 e 3 1 u 3
               After substitution,
                              q
                          .D z 3 5 cz 2 2 z 2 e 4 2 ~ x 4 z 2 2 e 4 ~ x 2 2 z 3 1 u 3  ð19:34Þ
            and the Lyapunov function up to this stage is:
                                               1
                                      V 3 5 V 2 1  z 2 3
                                               2
                                  q         2   2      q
                               .D V 3 #2 az 2 az 1 z 3 D z 3
                                            1   2
               Now, for e 4 5 α 3 , as the virtual controller,
                     q        2    2
                   D V 3 #2 az 2 az 1 z 3 cz 2 2 z 2 e 4 2 ~ x 4 z 2 2 e 4 ~ x 2 2 z 3 1 u 3 Š
                                        ½
                              1    2
               Keeping α 3 5 0, the controller can be chosen as:
                                     u 3 52 cz 2 1 ~ x 4 z 2
            which leads to
                                                 2
                                            2
                                   q
                                  D V 3 #2 az 2 az 2 z 2 3
                                            1
                                                 2
               Next from the last equation with z 4 5 e 4 2 α 3
                             q
                            D z 4 5 e 2 e 3 1 ~ x 3 e 2 1 ~ x 2 e 3 2 be 4 1 u 4
                                q                                    ð19:35Þ
                            .D z 4 5 z 2 z 3 1 ~ x 3 z 2 1 ~ x 2 z 3 2 be 4 1 u 4
               Lyapunov function will be:
                                               1
                                      V 4 5 V 3 1  z 2 4
                                               2
                      q        2    2   2
                  .D V 4 #2 az 2 az 2 z 1 z 4 ðz 2 z 3 1 ~ x 3 z 2 1 ~ x 2 z 3 2 be 4 1 u 4 Þ
                               1    2   3
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