Page 141 - Matrix Analysis & Applied Linear Algebra
P. 141

3.9 ElementaryMatrices and Equivalence                                             135

                                    Furthermore, by permuting the rows of E 1 and E 2 to force the pivotal 1’s to
                                    occupy the diagonal positions, we see that
                                                            row              row
                                                         E 1 ∼ T 1   and  E 2 ∼ T 2 ,              (3.9.5)
                                    where T 1 and T 2 are upper-triangular matrices in which the basic columns in
                                    each T i occupy the same positions as the basic columns in E i . For example, if
                                                                                    
                                                         120                    120
                                                   E =    001    , then T =    000   .
                                                         000                    001

                                                                    2
                                    Each T i has the property that T = T i because there is a permutation
                                                                    i
                                    matrix Q i (a product of elementary interchange matrices of Type I) such that

                                                T
                                         Q i T i Q =  I r i  J i  or, equivalently, T i = Q T  I r i  J i  Q i ,
                                                                                     i
                                                i
                                                      0   0                              0   0
                                                                              2
                                    and Q T  = Q −1  (see Exercise 3.9.4) implies T = T i . It follows from (3.9.5)
                                                i
                                          i
                                                                              i
                                           row
                                    that T 1 ∼ T 2 , so there is a nonsingular matrix R such that RT 1 = T 2 . Thus
                                                                  and   T 1 = R −1 T 2 = R −1 T 2 T 2 = T 1 T 2 .
                                      T 2 = RT 1 = RT 1 T 1 = T 2 T 1
                                    Because T 1 and T 2 are both upper triangular, T 1 T 2 and T 2 T 1 have the same
                                    diagonal entries, and hence T 1 and T 2 have the same diagonal. Therefore, the
                                    positions of the basic columns (i.e., the pivotal positions) in T 1 agree with those
                                    in T 2 , and hence E 1 and E 2 have basic columns in exactly the same positions.
                                    This means there is a permutation matrix Q such that

                                                          I r  J 1                 I r  J 2
                                                 E 1 Q =             and  E 2 Q =          .
                                                          0   0                    0   0
                                    Using (3.9.4) yields PE 1 Q = E 2 Q, or

                                                       P 11  P 12  I r  J 1    I r  J 2
                                                                           =           ,
                                                       P 21  P 22   0  0        0   0
                                    which in turn implies that P 11 = I r and P 11 J 1 = J 2 . Consequently, J 1 = J 2 ,
                                    and it follows that E 1 = E 2 .
                                        In passing, notice that the uniqueness of E A implies the uniqueness of the
                                                                                                   row
                                    pivot positions in any other row echelon form derived from A. If A ∼ U 1
                                          row
                                    and A ∼ U 2 , where U 1 and U 2 are row echelon forms with different pivot
                                    positions, then Gauss–Jordan reduction applied to U 1 and U 2 would lead to
                                    two different reduced echelon forms, which is impossible.
                                        In §2.2 we observed the fact that the column relationships in a matrix A
                                    are exactly the same as the column relationships in E A . This observation is a
                                    special case of the more general result presented below.
   136   137   138   139   140   141   142   143   144   145   146