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300 Chapter 5 Norms, Inner Products, and Orthogonality
Example 5.4.5
−1
Problem: Determine the Fourier expansion of x = 2 with respect to the
1
standard inner product and the orthonormal basis given in Example 5.4.4
1 1 −1
1 1 1
1
B = u 1 = √ −1 , u 2 = √ , u 3 = √ −1 .
2 3 6
0 1 2
Solution: The Fourier coefficients are
−3 2 1
ξ 1 = u 1 x = √ , ξ 2 = u 2 x = √ , ξ 3 = u 3 x = √ ,
2 3 6
so
−3 2 −1
1 1 1
2
x = ξ 1 u 1 + ξ 2 u 2 + ξ 3 u 3 = 3 + + −1 .
2 3 6
0 2 2
3
Youmay find it instructive to sketch a picture of these vectors in .
Example 5.4.6
Fourier Series. Let V be the inner-product space of real-valued functions
that are integrable on the interval (−π, π) and where the inner product and
norm are given by
π π 1/2
2
f|g = f(t)g(t)dt and f = f (t)dt .
−π −π
It’s straightforward to verify that the set of trigonometric functions
B = {1, cos t, cos 2t, . . ., sin t, sin 2t, sin 3t, . . .}
is a set of mutually orthogonal vectors, so normalizing each vector produces the
orthonormal set
!
1 cos t cos 2t sin t sin 2t sin 3t
B = √ , √ , √ ,..., √ , √ , √ ,... .
2π π π π π π
Given an arbitrary f ∈V, we construct its Fourier expansion
∞
∞
1 cos kt sin kt
F(t)= α 0 √ + α k √ + β k √ , (5.4.4)
2π π π
k=1 k=1