Page 64 - Singiresu S. Rao-Mechanical Vibrations in SI Units, Global Edition-Pearson (2017)
P. 64

1.7  sprinG elements   61
                                                            W   k d
                                                                1 1
                                     k 1
                                                      k 1       k 1
                                                                W
                                              1 d
                                                                     2 2
                                     k 2                         W   k d
                                                                k 2
                                                      k 2
                                              1 d
                                         st d                 W
                                              2 d
                                                     W        W

                                       (a)          (b)       (c)
                                    FiGure 1.28  Springs in series.


                                    If k  denotes the equivalent spring constant, then for the same static deflection,
                                       eq
                                                                   W = k d                             (1.14)
                                                                         eq st
                                    Equations (1.13) and (1.14) give

                                                               k d = k d = k d
                                                                       2 2
                                                                             eq st
                                                                1 1
                                    or
                                                                k d             k d
                                                                 eq st
                                                                                 eq st
                                                           d =       and d =                           (1.15)
                                                            1
                                                                 k 1        2    k 2
                                    Substituting these values of d  and d  into Eq. (1.12), we obtain
                                                                 2
                                                           1
                                                               k d   +  k d
                                                                eq st
                                                                        eq st
                                                                 k 1    k 2  = d st
                                    That is,
                                                                  1     1    1
                                                                     =    +                            (1.16)
                                                                  k eq  k 1  k 2
                                    Equation (1.16) can be generalized to the case of n springs in series:

                                                             1    1    1          1
                                                                =    +   + g +                         (1.17)
                                                            k eq  k 1  k 2        k n
                                    In certain applications, springs are connected to rigid components such as pulleys, levers,
                                    and gears. In such cases, an equivalent spring constant can be found using energy equiva-
                                    lence, as illustrated in Examples 1.8 and 1.9.
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