Page 171 - Mechanics Analysis Composite Materials
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156                 Mechanics and analysis of composite materials

             calculated with the aid of Eqs. (4.69) and (4.77). As can be seen in this figure, the
             best angle is about 10". At this angle, shear strain yI2 is much higher than the normal
             strains 81  and ~2,so that material deformation is associated mainly with shear. Off-
             axis test with d, = 10" can be also used  to evaluate material strength in shear 212
             (Chamis,  1979). Stresses acting under  off-axis tension  in  the  principal  material
             coordinates are statically determinate and can be found directly from Eqs. (4.67) as

                 01  = o,cos 2 4,  a2  = oxsin2 4,   212 = --a,sin&cos4  .     (4.78)

             Thus, applying stress a,  and changing d, we can induce a proportional loading with
             different combinations of stresses a],62, and 212 to evaluate constitutive or failure
             theory for a material under study.
               However, the test shown in Fig. 4.23 can hardly be performed because the test
             fixture (see Fig. 4.22) restrains the shear deformation of the specimen. This restraint
             does not  demonstrate itself  only if  shear is not  induced by  the  off-axis tension,
             i.e., if  yv  = 0 in Eqs. (4.77). This means that  qXys = 0 or that in accordance with
             Eqs. (4.76),






             This  equation  has  two  natural  solutions  4 = 0  and  4 = 90"  corresponding to
             tension along and across the fibers. However, it can have one more solution, i.e.,

                           1+121   I
                 sin2 d, =   El   2G12                                         (4.79)
                         I+m   I+VlZ   1  .
                         EI         Giz
             Because 0 < sin2d, < 1, solution for this equation exists if


                                                                               (4.80)


             Unfortunately, these conditions cannot be satisfied for unidirectional composites.
             Indeed, as follows from Eqs. (4.76), there exists the following differential relation
             between compliance coefficients (Verchery and Gong, 1999):

                              VXJV
                 $(t)= -2G,,

             This  means  that  vXJy = 0  if  E,  reaches its  extremum  value  within  the  interval
             0 < 4 < 90". In other words, function E,(4) should be as shown in Fig. 4.25 with a
             solid line. Then, uxsy = 0 at 4 = 4,,.  But for unidirectional advanced composites
             whose properties are listed in Table 3.5, the curve is similar to the broken line in
             Fig. 4.25, and E,  reaches its extremum values at d, = 0 and 4 = 90" only.
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