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Thermodynamics of Chemical Reactions   91

                                Table 2-3 gives the results of the program for the heats of reaction
                              at 298 K and 623 K, respectively



                                                        Example 2-4
                                Experimental values calculated for the heat capacity of ammonia
                              from –40 to 1200°C are shown in Table 2-4.
                                Fit the data by least squares for the following two functions.


                                 C =+      +   2
                                  o
                                     a bT cT
                                  p
                                     a bT cT +
                                 C =+      +   2  dT 3
                                  o
                                  p
                              Solution

                                A computer program, PROG2, was developed to fit the data by
                              least squares of a polynomial regression analysis. The data of tempera-
                              ture (independent variable) versus heat capacity (dependent variable)
                              were inputted in the program for an equation to an nth degree
                                                    2
                                                                           n
                                                            3
                              Y = C  + C X + C X  + C X + . . . + C X .  The results of the
                                    o     1      2       3              n
                                                                                  o
                              computer program for the polynomial regressions of: C  = a + bT +
                                                                                  p
                                       o
                                                       2
                                                              3
                                2
                              cT  and C  = a + bT + cT  + dT  are:
                                        p
                                          +
                                  o
                                      .
                                                           .
                                             .
                                 C =8 357 0 818  ×10 −2 T − 0 16807 ×10 −5  T 2  cal
                                  p
                                                                               o
                                                                          gmol C
                                                          Table 2-4
                               T                   C o p             T                 C o p
                              °C             cal/gmolT• °C           °C           cal/gmol • °C
                              –40                 8.180              500              12.045
                              –20                 8.268              600              12.700
                              0                   8.371              700              13.310
                              18                  8.472              800              13.876
                              25                  8.514              900              14.397
                              100                 9.035             1,000             14.874
                              200                 9.824             1,100             15.306
                              300                10.606             1,200             15.694
                              400                11.347
                              Source: Basic Principles and Calculations in Chemical Engineering by David M. Himmelblau,
                              5th ed., 1989, Prentice Hall International series.
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