Page 65 - Modelling in Transport Phenomena A Conceptual Approach
P. 65

46                             CHAPTER 3.  INTERPHASE TRANSPORT
















                                Figure 3.3  Flow over a flat plate.


               As an engineer we are interested in the total rate of heat transfer from the plate
            to the flowing stream.  This can be calculated by integrating the total energy flux
            at the wall over the surface area.  The total energy flux at the wall,  e,l,,o,   is
                                                                              (3.2-1)

            where qvlY=o is the molecular (or, conductive) energy flux at the wall.  As a result
            of  the no-slip boundary condition at the wall, the fluid in contact with the plate
            is stagnant  and  heat  is transferred  by  pure  conduction through  the  fluid  layer
            immediately adjacent to the plate.  Therefore, Eq.  (3.2-1) reduces to

                                       eYly=0 = QYIar=O  = 4u                 (3.2-2)
            and the rate of heat transfer, Q, from one side of the plate to the flowing stream is


                                      Q = Jd"  Jd"  qw dxdz                   (3.2-3)

            Evaluation of  the integral in Eq.  (3.2-3) requires the determination of the temper-
            ature gradient at the wall. However, the fluid motion makes the analytical solution
            of the temperature distribution impossible to obtain in most cases. Hence, we usu-
            ally resort to experimentally determined values of  the energy flux at a solid-fluid
            boundary in terms of  the convection heat transfer weficient, h, as
                                                                              (3.2-4)

            which  is  known  as Newton's  law  of woling.  The convection heat  transfer  coef-
            ficient, h, has the units of  W/m2.K.  It  depends on the fluid flow mechanism,
            fluid properties  (density, viscosity, thermal conductivity, heat capacity)  and flow
            geometry.
               Substitution of Eq. (3.2-4) into Eq.  (3.2-3) gives the rate of heat transfer as

                        Q = (T, - Tm) Jd"  1" hdxdz = (WL)(h)(T, - T,)        (3.2-5)
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