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1400-CH06  9/9/99  7:40 AM  Page 145






                                                                                 Chapter 6 Equilibrium Chemistry  145

                     Equilibrium constants for complexation reactions involving solids are defined
                 by combining appropriate K sp and K f expressions. For example, the solubility of
                 AgCl increases in the presence of excess chloride as the result of the following com-
                 plexation reaction
                                                –
                                                            –
                                      AgCl(s)+Cl (aq) t AgCl 2 (aq)              6.21
                 This reaction can be separated into three reactions for which equilibrium constants
                 are known—the solubility of AgCl, described by its K sp
                                                  +
                                                          –
                                       AgCl(s) t Ag (aq)+Cl (aq)
                                              –
                 and the stepwise formation of AgCl 2 , described by K 1 and K 2
                                                 –
                                         +
                                       Ag (aq)+Cl (aq) t AgCl(aq)
                                                 –
                                                            –
                                     AgCl(aq)+Cl (aq) t AgCl 2 (aq)
                 The equilibrium constant for reaction 6.21, therefore, is equal to K sp ´K 1 ´K 2 .
                     EXAMPLE 6.4

                     Determine the value of the equilibrium constant for the reaction
                                            PbCl 2 (s) t PbCl 2 (aq)

                     SOLUTION
                     This reaction can be broken down into three reactions. The first of these
                     reactions is the solubility of PbCl 2 , described by its K sp
                                                   2+
                                                             –
                                        PbCl 2 (s) t Pb (aq) + 2Cl (aq)
                     and the second and third are the stepwise formation of PbCl 2 (aq), described by
                     K 1 and K 2
                                          2+
                                                             +
                                                   –
                                        Pb (aq)+Cl (aq) t PbCl (aq)
                                                   –
                                           +
                                       PbCl (aq)+Cl (aq) t PbCl 2 (aq)
                     Using values for K sp , K 1 , and K 2 from Appendices 3A and 3C, we find the
                     equilibrium constant to be
                                                     –5
                              K = K sp ´K 1 ´K 2 = (1.7 ´10 )(38.9)(1.62) = 1.1 ´10 –3



                 6D. 4  Oxidation–Reduction Reactions
                 In a complexation reaction, a Lewis base donates a pair of electrons to a Lewis acid.
                 In an oxidation–reduction reaction, also known as a redox reaction, electrons are  redox reaction
                 not shared, but are transferred from one reactant to another. As a result of this elec-  An electron-transfer reaction.
                 tron transfer, some of the elements involved in the reaction undergo a change in ox-
                 idation state. Those species experiencing an increase in their oxidation state are oxi-
                 dized, while those experiencing a decrease in their oxidation state are reduced. For
                 example, in the following redox reaction between Fe 3+  and oxalic acid, H 2 C 2 O 4 ,
                 iron is reduced since its oxidation state changes from +3 to +2.
                                                                           +
                         3+
                                                       2+
                      2Fe (aq)+H 2 C 2 O 4 (aq)+2H 2 O(l) t 2Fe (aq) + 2CO 2 (g)+2H 3 O (aq) 6.22
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