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148 Modern Analytical Chemistry
Solving for K gives the equilibrium constant as
log K = 40.6558
K = 4.527 ´10 40
+
2+
(c) The potential when the [Ag ] is 0.020 M and the [Cd ] is 0.050 M is
calculated using equation 6.24 employing the appropriate relationship for
the reaction quotient Q.
. 0 05916 [Cd 2 + ]
°
E = E – log
n [Ag + 2
]
. 0 05916 (. 0 050 )
= . 1 2026 – log
2 (. 0 020 ) 2
= . 114V
6E Le Châtelier’s Principle
The equilibrium position for any reaction is defined by a fixed equilibrium con-
stant, not by a fixed combination of concentrations for the reactants and products.
This is easily appreciated by examining the equilibrium constant expression for the
dissociation of acetic acid.
[H O + ][CH COO – ]
3
3
K a = = . 175 ´10 –5 6.26
[CH COOH ]
3
As a single equation with three variables, equation 6.26 does not have a unique so-
+
–
lution for the concentrations of CH 3 COOH, CH 3 COO , and H 3 O . At constant
+
temperature, different solutions of acetic acid may have different values for [H 3 O ],
–
[CH 3 COO ] and [CH 3 COOH], but will always have the same value of K a .
If a solution of acetic acid at equilibrium is disturbed by adding sodium acetate,
–
the [CH 3 COO ] increases, suggesting an apparent increase in the value of K a . Since
K a must remain constant, however, the concentration of all three species in equa-
tion 6.26 must change in a fashion that restores K a to its original value. In this case,
+
–
equilibrium is reestablished by the partial reaction of CH 3COO and H 3O to pro-
duce additional CH 3 COOH.
The observation that a system at equilibrium responds to a stress by reequili-
Le Châtelier’s principle brating in a manner that diminishes the stress, is formalized as Le Châtelier’s prin-
When stressed, a system that was at ciple. One of the most common stresses that we can apply to a reaction at equilib-
equilibrium returns to its equilibrium rium is to change the concentration of a reactant or product. We already have seen,
state by reacting in a manner that
relieves the stress. in the case of sodium acetate and acetic acid, that adding a product to a reaction
mixture at equilibrium converts a portion of the products to reactants. In this in-
stance, we disturb the equilibrium by adding a product, and the stress is diminished
by partially reacting the excess product. Adding acetic acid has the opposite effect,
partially converting the excess acetic acid to acetate.
In our first example, the stress to the equilibrium was applied directly. It is also
possible to apply a concentration stress indirectly. Consider, for example, the fol-
lowing solubility equilibrium involving AgCl
–
+
AgCl(s) t Ag (aq)+Cl (aq) 6.27