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                                                               Chapter 7 Obtaining and Preparing Samples for Analysis  203

                 where C I is the concentration of interferent remaining after the separation, and
                 (C I ) o is the interferent’s initial concentration. The degree of separation is given by a
                 separation factor, S I,A , which is the change in the ratio of interferent to analyte  separation factor
                 caused by the separation. 11                                            A measure of the effectiveness of a
                                                                                         separation at separating an analyte from
                                                 I /
                                                CC A       R I                           an interferent (S I,A ).
                                        S I,A =          =
                                              ( C Io ) /( C A o )  R A

                            7
                     EXAMPLE  .10
                     An analysis to determine the concentration of Cu in an industrial plating bath
                     uses a procedure for which Zn is an interferent. When a sample containing
                     128.6 ppm Cu is carried through a separation to remove Zn, the concentration
                     of Cu remaining is 127.2 ppm. When a 134.9-ppm solution of Zn is carried
                     through the separation, a concentration of 4.3 ppm remains. Calculate the
                     recoveries for Cu and Zn and the separation factor.
                     SOLUTION
                     The recoveries for the analyte and interferent are

                                          127 2 ppm
                                             .
                                     R Cu =         =0 9891,  or  98 91%
                                                       .
                                                                 .
                                             .
                                          128 6 ppm
                     and
                                             43 ppm
                                              .
                                      R Zn =          =0 032,  or  3 2%
                                                                .
                                                        .
                                            134 9 ppm
                                              .
                     The separation factor is
                                                       .
                                               R Zn   0 032
                                       S Zn,Cu =    =       =0 032
                                                              .
                                                      .
                                               R Cu  0 9891
                 In an ideal separation R A = 1, R I = 0, and S I,A = 0. In general, the separation factor
                                        –7
                 should be approximately 10 for the quantitative analysis of a trace analyte in the
                                                 –3
                 presence of a macro interferent, and 10 when the analyte and interferent are pres-
                 ent in approximately equal amounts.
                     Recoveries and separation factors are useful ways to evaluate the effectiveness
                 of a separation. They do not, however, give a direct indication of the relative error
                 introduced by failing to remove all interferents or failing to recover all the analyte.
                 The relative error introduced by the separation, E, is defined as
                                                    -  *
                                                S samp  S samp
                                           E =                                   7.14
                                                    *
                                                   S samp
                        *
                 where S samp is the expected signal for an ideal separation when all the analyte is re-
                 covered.
                                              *
                                             S samp = k A(C A) o                 7.15
                 Substituting equations 7.12 and 7.15 into 7.14 gives
                                                           kC A o )
                                        kC +    K A,I  ´ C I )  - A (
                                         A (
                                            A
                                    E =
                                                  A (
                                                 kC A o )
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