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Optical System Layout  297











        Figure 13.5 The vignetting action of the eyelens determines the
        field of view in an astronomical telescope.



        apparent that the “effective” position of the exit pupil shifts inward as
        the amount of vignetting increases.
          Let us now determine the minimum power for a field lens which will
        completely eliminate the vignetting at a field angle of  0.0625 rad.
        From Fig. 13.6, it can be seen that the field lens must bend the rays
        from the objective so that ray B strikes no higher than the upper rim
        of the eyelens. The slope of ray B is equal to 1 in (the difference in the
        heights at which it strikes the objective and the field lens) divided by
        8 in (the distance from field lens to objective), or  0.125. After passing
        through the field lens, we desire the slope to be zero (in this case)
        as indicated by the dashed ray B′. Using Eq. 4.1, we can solve for the
        power of the field lens as follows:

                               u′   u   y
                                          f
                              0.0   0.125  (0.5)
                                                   f
                                   0.25
                                f
                                    1
                                f        4 in
                                f

















        Figure 13.6 Ray diagram used to determine field lens
        power in Example 13.1.
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