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Optical System Layout  301

        a 4  scope of 10-in length; we have not, however, included the eye
        relief in these equations. To resolve this situation numerically, we
        would now assume some reasonable value for f o , then proceed to test
        various values of f e , selecting the value of f e which yields the desired
        value for the eye relief R. Since R is not a critical dimension, a graphic
        solution (after a few values of f e have been tried), plotting R versus f e
        would be quite adequate for our purpose. Repeating the process for
        several additional values of f o would then indicate the range of solutions
        available.
          To arrive at a solution analytically, we would proceed as follows: a
        principal ray, starting at the center of the objective lens with some
        arbitrary slope angle would be ray-traced by thin-lens equations (4.1,
        4.2, and 4.3), using the symbolic values for the spacings and lens powers
        derived from the three equations immediately preceding. The symbolic
        values for the powers and spacings involved would thus be:

                                             f o (L   f o   f e)
               First airspace   f   s   f
                                o   1    o
                                               (Mf   f )
                                                  e   o
                                  1       (Mf   f ) 2
                                              e
                                                  o
               Erector power
                               r
                                  f     Mf f (L  f   f )
                                   r      e o     o   e
                                               Mf e (L   f o   f e)
               Second airspace   s   f   f
                                  2   e   e
                                                  (Mf   f )
                                                     e   o
                                   1
               Eyelens power
                               e
                                   f
                                    e
        The expression for the final intercept length of this ray, l′ e   y e /u′ e
        is then equated to the eye relief R, and a solution for f e expressed in
        terms of f o , M, L, and R is extracted. As can be imagined, the procedure
        is lengthy and the probability of making an error in the derivation is
        approximately unity for the first few attempts. Careful work and fre-
        quent checking are not only advisable, they are mandatory. When the
        smoke has cleared away, one finds that
                                              2
                                   2
                                 M RL   f o (M R   L)
                           f e
                                  2
                                M (R   L)  f o (M 1) 2
        and that for any chosen value for f o (which is less than L and more
        than zero), a set of powers and spacings can be obtained which will
        satisfy our original conditions for power M, length L, and eye relief R.
          We are now faced, regardless of whether we have arrived via num-
        bers or symbols, with the problem of determining what is a suitable
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