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110     3 Matrix eigenvalue analysis



                   In general if P ≤ N is the number of distinct roots of (3.39), we write
                           p(λ) = det(A − λI) = (λ 1 − λ) (λ 2 − λ) m 2  ··· (λ P − λ) m P  (3.41)
                                                     m 1
                   m k is the (algebraic) multiplicity of λ k , i.e., the number of times that it is repeated as a root
                   of (3.39). The multiplicities must sum to N,
                                            m 1 + m 2 + ··· + m P = N                 (3.42)

                   From p(λ = 0), we find the determinant to be the product of the eigenvalues,
                                                      m 1 m 2
                                             det(A) = λ λ  ...λ m P                   (3.43)
                                                      1  2    P
                   It may also be shown that the trace equals the sum of the eigenvalues,
                                                                                      (3.44)
                                 tr(A) = a 11 + a 22 +· · · + a NN = λ 1 + λ 2 +· · · + λ N
                   A proof of this result is found in the supplemental material in the accompanying website.


                   Eigenvalues and the existence/uniqueness properties
                   of linear systems


                   We now consider the existence and uniqueness properties of Ax = b from the viewpoint of
                   eigenvalue analysis. Let A be an N × N matrix, with the P distinct eigenvalues λ 1 , λ 2 ,...,
                                        [2]
                                    [1]
                   λ P for eigenvectors w , w ,..., w [P] ,
                                                Aw [k]  = λ k w [k]                   (3.45)

                   Let these P distinct eigenvalues be ordered by increasing modulus,
                                             |λ 1 |≤|λ 2 |≤· · · ≤|λ P |              (3.46)

                   We use the ≤ sign, even though the eigenvalues are distinct, because with complex eigen-
                   values we may have the distinct, but equal modulus, values

                                      λ k = a + ib  λ k+1 = a − ib  a, b ∈            (3.47)
                   We now examine the effect of A on an eigenvector associated with λ 1 ,

                                                Aw [1]  = λ 1 w [1]                   (3.48)
                   If any eigenvalue is zero, it will be λ 1 , as we have ordered the eigenvalues by increasing
                   modulus. Also, if λ 1 = 0, A is singular, as
                                                    m 1 m 2
                                           det(A) = λ λ  ··· λ m P  = 0               (3.49)
                                                    1  2     P
                   Thus, if λ 1 = 0, the null space of A is not empty and there exists some w ∈ K A , w  = 0
                   such that Aw = 0. But, when λ 1 = 0, as
                                               Aw [1]  = λ 1 w [1]  = 0               (3.50)

                   any eigenvector w [1]  for λ 1 = 0 is in the null space of A and dim(K A ) = m 1 .
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