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Eigenvector matrix decomposition and basis sets                     119



                                                                               −1
                  Proof The eigenvalues of B are roots of det(B − λI) = 0. Substituting B = S AS,
                                       det(B − λI) = det(S  −1 AS − λI) = 0          (3.94)
                                          −1
                                                −1
                  We now use the identity I = S S = S IS to obtain
                                                              −1
                        det(B − λI) = det(S −1 AS − λS −1 IS) = det(S (A − λI)S) = 0  (3.95)
                  Now, as det(AB) = det(A) × det(B),
                                                 −1
                                 det(B − λI) = det(S ) × det(A − λI) × det(S) = 0    (3.96)
                                      −1
                  As det(S)  = 0 and det(S )  = 0 for a nonsingular S, λ can only satisfy det(B − λI) = 0if
                                                           −1
                  it also satisfies det(A − λI) = 0. Thus, A and B = S AS have the same eigenvalues.
                                                   −1
                    Let Aw = λw. Substituting A = SBS ,wehave SBS −1  w = λw. Multiplying by S −1
                  yields the following relationship between eigenvectors of A and B:
                                                      −1
                                                               −1
                                        Aw = λw    B(S w) = λ(S w)                   (3.97)
                                                                                      QED

                                                      H
                  Definition The Hermitian conjugate of A, A , is obtained by taking the transpose of the
                  matrix and its complex conjugate,
                                                            H
                           A kj = a kj + ib kj  {a kj, b kj }∈   (A ) kj = a jk − ib jk  (3.98)
                                                                     H
                                                             H
                                                                  H
                  The Hermitian conjugate of a matrix product is (AB) = B A .
                                                                H
                  Definition A matrix A is said to be Hermitian if A = A . A real Hermitian matrix A is
                                T
                  symmetric, A = A .
                                                           H
                                                                 −1
                  Definition  A matrix U is said to be unitary if U = U . A real unitary matrix Q is
                                  −1
                             T
                  orthogonal, Q = Q .
                                                              H
                                                         H
                  Definition A matrix A is said to be normal if AA = A A. Hermitian and unitary matrices
                  are both special cases of normal matrices.
                  Theorem EVG4 We can write any complex matrix A in terms of a unitary matrix U and
                  upper triangular matrix R as the Schur decomposition,
                                                 A = URU  H                          (3.99)
                           −1
                      H
                  As U = U , A and R are similar, and as R is triangular, the diagonal elements of R are
                  eigenvalues of A. In MATLAB, a Schur decomposition is computed by schur.
                  Proof We proceed by induction, showing that if (3.99) holds for (N − 1) × (N − 1) matrices,
                  then it also does for N × N matrices. For N = 1, we have the trivial result

                                             U = 1    A = R = λ                     (3.100)

                                                                        [2]
                  For an N × N matrix A, let Aw = λw, |w|= 1, and let {w, u ,..., u [N] } form an
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