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Existence and uniqueness of solutions                                 23



                  in the third row. We thus swap rows 2 and 3,
                                                                 
                                                     3  1   6   2
                                          ¯ ¯ (3, 1)
                                        (A, b)   =  0  2 3  −13  1                (1.117)
                                                   
                                                                 3 
                                                     0  1  −15   2
                                                        3        3
                  and perform a row operation to zero the (3, 2) element.

                                                  1      2     1
                                            λ 32 =          =                       (1.118)
                                                  3      3     2
                                                                               
                                       3      1            6             2
                          (A, b) (3, 2)  =   0  2 3      −1            3 1 3   
                                     
                                                                                
                                                                         1
                                                 2
                                            1  1           1         2        1
                                       0    −         −1 − (−1)     5 −     3
                                           3   2  3        2         3   2    3
                                                   
                                       3  1   6   2
                                       0  2  −1  3  1                             (1.119)
                                          3        3 
                                   = 
                                       0  0  − 1  4
                                               2
                  We now have an upper triangular system to solve by backward substitution,
                                             3x 1 + x 2 + 6x 3 = 2
                                                   2  x 2 − x 3 = 3  1              (1.120)
                                                   3          3
                                                       1
                                                     − x 3 = 4
                                                       2
                  First, x 3 =−8 from the last equation. Then, from the second equation,
                                                 1        2

                                           x 2 = 3 + x 3    =−7                     (1.121)
                                                 3        3
                  Finally, from the first equation,
                                          x 1 = (2 − 6x 3 − x 2 )/3 = 19            (1.122)
                  The solution to (1.70) is thus (x 1 , x 2 , x 3 ) = (19, −7, −8).
                  Existence and uniqueness of solutions


                  With Gaussian elimination and partial pivoting, we have a method for solving linear systems
                  that either finds a solution or fails under conditions in which no unique solution exists. In
                  this section, we consider at more depth the question of when a linear system possesses a real
                  solution (existence) and if so, whether there is exactly one (uniqueness). These questions are
                  vitally important, for linear algebra is the basis upon which we build algorithms for solving
                  nonlinear equations, ordinary and partial differential equations, and many other tasks.


                  Interpreting Ax = b as a linear transformation
                  As a first step, we consider the equation Ax = b from a somewhat more abstract viewpoint.
                  We note that A is an N × N real matrix and x and b are both N-dimensional real vectors.
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