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46      1 Linear algebra




                             2      1
                               2 w
                                 1
                               2
                                w             2
                                 2
                               2 w
                    1    1                w
                                           1
                                          w   2
                   1 w   2                 2
                    1
                   1                      w   22
                   w
                    2
                   1
                   w   2

                                          w   2
                                           1
                                          w
                                           2
                                          w
                   Figure 1.9 Process diagram for separation system.
                   1.  the total mass flow rate
                                            2     4     5     1
                                             F + F + F =       F                     (1.230)
                   2.  the mass flow rate of species 1
                                 2
                                                     5
                                                           5
                                                                  1
                                         4
                                                                       1
                            2
                                              4
                           ( w 1 )( F ) + ( w 1 )( F ) + ( w 1 )( F ) = ( w 1 )( F )  (1.231)
                   3.  the mass flow rate of species 2
                                                                       1
                                                                  1
                                              4
                                                     5
                                                          5
                           2
                                 2
                                        4
                          ( w 2 )( F ) + ( w 2 )( F ) + ( w 2 )( F ) = ( w 2 )( F )  (1.232)
                   This yields the set of three algebraic equations
                                               x 1 + x 2 + x 3 = 10
                                         (0.04)x 1 + (0.54)x 2 + (0.26)x 3 = 2       (1.233)
                                         (0.93)x 1 + (0.24)x 2 + (0.0)x 3 = 6
                   Gaussian elimination yields
                                    x 1 = 5.8238  x 2 = 2.4330  x 3 = 1.7433         (1.234)
                   sep system example.m performs this calculation. For further discussion of the formula-
                   tion of material and energy balances, and algorithms for their solution, consult Reklaitis
                   (1983).
                   Sparse and banded matrices


                   In the example above, the mathematical formulation of the problem was indeed a linear
                   system, and we could apply Gaussian elimination directly. Most mathematical problems,
                   however, are not expressed naturally as linear systems. Still, the availability for linear sys-
                   tems of rigorous existence and uniqueness conditions and an automated solution procedure
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