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Wet Gases Chapter | 4  81



               TABLE 4.11 Reservoir and Fluid Parameters for the Two Samples
               Parameter                   Unit      Reservoir 1  Reservoir 2
               Fluid sample                          Sample 1     Sample 2
               Initial reservoir pressure  psia      10,000       5498
               Reservoir temperature         F       204          290
               Total producing GOR         scf/STB   14,325       63,695
               Reservoir area              ac        12,000       10,000
               Average reservoir net pay thickness  ft  35        40
               Average porosity            Fraction  0.18         0.23
               Average initial water saturation  Fraction  0.32   0.19
               GOR, gas oil ratio.


                                             f g G T
                                         N 5                           ð4:14Þ
                                              R t
                The fraction of the total initial gas in place that will be produced in the
             gaseous phase at the surface is calculated from Eq. 4.15.

                                              R t
                                 f g 5                                 ð4:15Þ
                                     R t 1 132; 800γ =M o
                                                  o

             Problem 4—Calculating Hydrocarbon in Place for Wet Gases
             The two fluid samples above were taken from two different reservoirs with
             the basic reservoir data given in Table 4.11. Estimate the total initial gas in
             place, the fraction of the total initial gas in place that will be produced in the
             gaseous phase, and the initial oil (condensate) in place.

             Solution of Problem 4
             By use of the following volumetric calculation for total initial gas in place
             (Eq. 4.16), the total (gas with the vaporized condensate) gas in place can be
             calculated.

                                       7758 Ah ø1 2 S wi Þ
                                                ð
                                  G T 5                                ð4:16Þ
                                              B gi
                As an example calculation for Reservoir 1:
                           ð
                     ð 7758Þ 12; 000Þ 35Þ 0:18Þð1 2 0:32Þ   11
                                     ð
                                  ð
                G T 5                              5 1:4 3 10  scf 5 0:14 tcf
                                 0:00284
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