Page 330 - Petroleum and Gas Field Processing

0:7895 !
11
h Z ¼ 31:25 0:5505 0:2646 ¼ 7:5ft
ð45Þ ð100Þ
0
X S ðh B 0:45 h z Þ
X C ¼
h B
X S ¼ 7:407 þ 0:09357ð100Þ¼ 16:764
0
X S ¼ 16:764½1:518 0:00673ð100ފ ¼ 14:17
14:17½16:3 0:45ð7:5ފ
X C ¼
16:3
¼ 11:236 lbs H 2 O=100 lbs solid

or
X C ¼ 0:1124 lbs H 2 O=lb solid ðper lb solidÞ

Initially, we assumed X C ¼ 0.12, which is close enough.
0:01X h
C B B
B ¼
q
0:01ð11:2Þð45Þð16:3Þ
B ¼ ¼ 7:468
11

So, assuming three cycles each 8 h will be fine.
The pressure drop P (psia) is calculated as
P 5 2
¼ 0:0560 V g þ 8:89 10 V g
h B

5
2
P ¼ 0:0560ð0:01Þð45Þþ 8:89 10 ð1:5Þð45Þ ð16:3Þ¼ 4:8 psi
which is less than 8 psia (recommended).

12.5.3 Regeneration Heat Requirements
The heat required during the heating part of the cycle is

Q H ¼ m d ðT m T a ÞC d þ m 1 ðT m T a ÞC t þ w 1 H d þ w 1 ðT av T a Þ
ð22Þ

T m þ T a
T av ¼
2

Copyright 2003 by Marcel Dekker, Inc. All Rights Reserved.