Page 282 - Petrophysics 2E
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FLOW UNITS FOR  SWY SANDSTONES               255


                           exponent n are constant within a given flow unit. In order to identify flow
                           units, a permeability-porosity relationship is necessary. This relationship
                           is then combined with a shale model that best describes the pay zone of
                           interest, to derive the slope Hsh and intercept FZI,h.  If, for instance, the
                           saturation exponent is equal to 2, the total shale model can simply be
                           written as:


                                                                                       (4.106)



                           The Timur permeability-porosity relationship is:

                                    ($4.4
                           k = 85817-                                                  (4.107)
                                    sw

                           The Wyllie and Rose relationship is:

                           k = 62,500, o6
                                     sw                                                (4.108)

                           The generalized form of  the Timur or Wyllie  and  Rose  permeability-
                           porosity model is:


                                                                                       (4.109)


                           where  C1  and  C2  are  correlation  constants.  In  the  case  of  Timur
                           (Equation 4.103, n  = 2, C1  = 8581, and C2  = 4.4, where k is in mD
                           and porosity and saturation are expressed in fractions. For the Wyltie
                           and Rose equation (Equation 4.108), n = 2, C1  = 62,500, and C2  = 6,
                           where k is in mD and @ and S, are fractions.
                             Assuming the pay zone has low shale content (v,h  -=  lo%), i.e. csh is
                           approximately zero, then combining Equations 4.101 , 4.106, and 4.109
                           and solving for RQI yields:

                           Log(RQ1) = (




                           Assuming Wyllie and Rose is applicable and substituting for C1 and CZ
                           gives:
                                                              (  E>
                           Log(RQ1) = (0.5m + 2.5) Logo + Log  78.5  -                 (4.111)
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