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5 14   PETROPHYSICS: RESERVOIR ROCK PROPERTIES



                     resistivity  = 85  ohm-m.  The  reservoir  average  porosity  (17%)  was
                     determined from a Neutron log. Substantial mud loss was observed during
                     drilling of this well as well as in neighboring wells. Pressure test analysis
                     as well as cores confirmed the presence of extensive natural fractures in
                     the well.

                     (a)  Estimate the fracture intensity index and the porosity partitioning
                        coefficient.
                     (b)  If the average irreducible water saturation estimated from log analysis
                        is 24%, determine the fracture width. Note that the coefficient CX in
                         equation 8.12 is typically 0.25.
                     (c)  Estimate  the  fracture  width,  fracture  permeability  and  fracture
                         porosity of the formation.


                     SOLUTION

                     (a)  Knowing RLLS = Rxo = 12 and Rm = Rt = 85, the fracture intensity
                         index is estimated from Eq. 8.18:

                                1     I

                         FII =   Rxo   Rt  -   1/12 - 1/85   = 0.1417
                                1     1  - l/0.165 - 1/0.18


                         The saturation of mud filtrate in the flushed zone is:


                         S,,  = S2 = 0.24°.25 = 0.70

                         The porosity partitioning coefficient is calculated using equation 8.13:






                           -       0.18       (L - ifi)  = 0.165
                           -
                             O.li’(0.24 - 0.70)  85

                     (b) Using Equation 8.19a:

                              0.064
                                    [(l
                         Wf  = - - Siw)FII]1.315
                                ot
                              0.064
                            - --    [(l - 0.24)(0.1417)]’.315 = 0.02 cm
                               0.17
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