Page 570 - Petrophysics
P. 570

CHARACTERIZING NATURAL. FRACTURES              537

                            EXAMPLE


                              A well is completed in a naturally fractured reservoir. Knowing the
                            following data, which were  obtained from core analysis and a single
                            pressure drawdown test:


                            h = 2.5 x         r,  = 0.3 ft   kf = 39,000 mD   k,  = 0.185 mD

                            (a)  Calculate the side length of the matrix blocks.
                            (b) What would be the height of the fracture zone if the system were
                                layered?


                            SOLUTION


                            (a)  The side length X,  is calculated from Equation 8.73:


                                          --
                                Xm=rw /F - o.3Jdou(llXs-                   = 15.3 ft
                                                       2.5 x      x 39,000

                            (b)  The fracture height is calculated from Equation 8.72:








                              Both of  the Warren  and Root parameters, h and a, are preferably
                            obtained from well test data by using either the conventional semi-log
                            analysis or the type curve matching techniques. Using the Tiub’s Direct
                            Synthesis technique both parameters can be determined from the log-log
                            plot of the pressure derivative versus time without using the typecurve
                            matching technique [29].
                              Figure 8.27 is the semi-log pressure test, with a typical two parallel
                            lines indicating presence of natural fractures. The storage capacity ratio
                            can be estimated from this figure, using the following equation:


                            o = exp (-2.303:)                                            (8.74)


                            where 6P is the pressure difference between  the two parallel lines in
                            Figure 8.24 and m is the slope of  either line. The degree of  fracturing
                            in each segment of the reservoir can influence the estimated value of O;
                            consequently testing different wells can yield diEferent values of 0.
   565   566   567   568   569   570   571   572   573   574   575