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142    REACTION SPONTANEITY AND THE DIRECTION OF THERMODYNAMIC CHANGE



                         provided that we know the way C p varies with temperature, expressed as a mathematical
                         power series in T . For example, C p for liquid chloroform CHCl 3 is

                                                                       −2
                                          C p /JK −1  mol −1  = 91.47 + 7.5 × 10 T
                           Alternatively, because Equation (4.9) has the form of an integral, we could plot a
                         graph of C p ÷ T (as y) against T (as x) and determine the area beneath the curve. We
                         would need to follow this approach if C p ÷ T was so complicated a function of T that
                         we could not describe it mathematically.




                                              Justification Box 4.1

                         Entropy is the ratio of a body’s energy to its temperature according to the Clausius
                         equality (as defined in the next section). For a reversible process, the change in entropy
                         is defined by
                                                           dq
                                                      dS =                               (4.11)
                                                            T
                         where q is the change in heat and T is the thermodynamic temperature. Multiplying
                         the right-hand side of Equation (4.11) by dT/dT (which clearly equals one), yields
                                                         dq   dT
                                                    dS =    ×                            (4.12)
                                                         T    dT
                         If no expansion work is done, we can safely assume that q = H. Substituting H for q,
                         and rearranging slightly yields

                                                        dH     1
                                                 dS =       ×   dT                       (4.13)
                                                        dT    T
                         where the term in brackets is simply C p . We write

                                                          C p
                                                     dS =    dT                          (4.14)
                                                          T
                         Solution of Equation (4.14) takes two forms: (a) the case where C p is considered not
                         to depend on temperature (i.e. determining the value of  S over a limited range of
                         temperatures) and (b) the more realistic case where C p is recognized as having a finite
                         temperature dependence.

                         (a) C p is independent of temperature (over small temperature ranges).

                                                  S 2        T 2  1
                                                    dS = C p     dT                      (4.15)
                                                               T
                                                 S 1         T 1
                         So
                                                S = S 2 − S 1 = C p [ln T ] T 2          (4.16)
                                                                    T 1
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