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228    PHASE EQUILIBRIA

                                      Because these two liquids, when mixed, obey Raoult’s law, we
              An ideal mixture com-   say they form an ideal mixture. In fact, relatively few pairs of
              prises a pair (or more)  liquids form ideal mixtures: a few examples include benzene and
              of liquids that obey
              Raoult’s law.           bromobenzene, benzene and toluene, bromobenzene and chloroben-
                                      zene, n-pentane and i-pentane. Note how each set represents a pair
                                      of liquids showing a significant extent of similarity.

                      SAQ 5.8 Benzene and toluene form an ideal mixture, i.e. they obey
                                         ◦                 O
                      Raoult’s law. At 20 C, the pressure p of benzene and toluene are 0.747 ×
                      p  O  and 0.223 × p  O  respectively. What is the pressure above a mixture of
                      these two liquids that contains 12 mol% of benzene?

                      Worked Example 5.9 (Continuing from Worked Example 5.8.) What are the mole frac-
                      tions of benzene and bromobenzene in the vapour?

                      From the definition of mole fraction x in Equation (5.11) above, we say

                                                     moles of benzene in the vapour
                                  x (benzene, vapour) =
                                                 total number of moles in the vapour phase
                      The numbers of moles n i are directly proportional to the partial pressures p i if we assume
                      that each vapour behaves as an ideal gas (we assume here that T , R and V are constant).
                      Accordingly, we can say

                                                        pressure of benzene
                                              x (benzene) =
                                                          total pressure

                                      Substituting numbers from Worked Example 5.8:
              Note how the units
              cancel to yield a dimen-                              42.9kPa
                                                          x (benzene) =
              sionless mole fraction.                               77.4kPa
                                                          x (benzene) = 0.554

                                      The mole fraction of benzene in the vapour is 0.554, so it contains 55.4
                                      per cent benzene. The remainder of the vapour comprises the second
              We need four mole
              fractions to define this  component bromobenzene, so the vapour contains (100 − 55.4)% =
              two-component sys-      44.6% of bromobenzene.
              tem – two for the liquid  Note how the liquid comprises 43 per cent benzene and 57 per
              phases and two for the  cent bromobenzene, but the vapour contains proportionately more of
              vapour phases.          the volatile benzene. We should expect the vapour to be richer in the
                                      more volatile component.

                      SAQ 5.9 Continuing with the system in SAQ 5.8, what is the mole fraction
                      of toluene in the vapour above the mixture?

                        In fact, most liquid mixtures do not obey Raoult’s law particularly well, owing to
                      molecular interactions.
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