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                  where h is the object’s altitude above the earth’s surface. As an object falls to earth, its  Section 2.1
                                                                  1
                                                                     2
                  potential energy mgh decreases and its kinetic energy  mv increases. Provided the     Classical Mechanics
                                                                  2
                  effect of air friction is negligible, the total mechanical energy K   V  remains constant
                  as the object falls.
                      We have considered a one-particle system. Similar results hold for a many-particle
                  system. (See H. Goldstein,  Classical Mechanics, 2d ed., Addison-Wesley, 1980,
                  sec. 1-2, for derivations.) The kinetic energy of an n-particle system is the sum of the
                  kinetic energies of the individual particles:
                                                               1  n
                                                     # # #
                                      K   K   K           K     a  m v 2             (2.23)
                                            1
                                                 2
                                                           n
                                                                     i i
                                                               2  i 1
                  Let the particles exert conservative forces on one another. The potential energy V of
                  the system is not the sum of the potential energies of the individual particles. Instead,
                  V is a property of the system as a whole. V turns out to be the sum of contributions due
                  to pairwise interactions between particles. Let V be the contribution to V due to the
                                                            ij
                  forces acting between particles i and j. One finds
                                                V    a a   V ij                      (2.24)
                                                      i  j 7i
                  The double sum indicates that we sum over all pairs of i and j values except those with i
                  equal to or greater than j.Terms with i   j are omitted because a particle does not exert
                  a force on itself. Also, only one of the terms V and V is included, to avoid counting
                                                         12
                                                                21
                  the interaction between particles 1 and 2 twice. For example, in a system of three parti-
                  cles, V   V   V   V .Ifexternal forces act on the particles of the system, their con-
                                 13
                                      23
                            12
                  tributions to V must also be included. [V is defined by equations similar to (2.17).]
                                                    ij
                      One finds that K   V   E mech  is constant for a many-particle system with only
                  conservative forces acting.
                      The mechanical energy K   V is a measure of the work the system can do. When
                  a particle’s kinetic energy decreases, the work–energy theorem w   K [Eq. (2.16)]
                  says that w, the work done on it, is negative; that is, the particle does work on the sur-
                  roundings equal to its loss of kinetic energy. Since potential energy is convertible to
                  kinetic energy, potential energy can also be converted ultimately to work done on the
                  surroundings. Kinetic energy is due to motion. Potential energy is due to the positions
                  of the particles.



                  EXAMPLE 2.1 Work

                     A woman slowly lifts a 30.0-kg object to a height of 2.00 m above its initial
                     position. Find the work done on the object by the woman, and the work done by
                     the earth.
                        The force exerted by the woman equals the weight of the object, which from
                                                         2
                     Eq. (2.6) is F   mg   (30.0 kg) (9.81 m/s )   294 N. From (2.10) and (2.11),
                     the work she does on the object is
                                        x 2
                                w      F1x2  dx   F¢x   1294 N212.00 m2   588 J
                                     x 1
                     The earth exerts an equal and opposite force on the object compared with the
                     lifter, so the earth does  588 J of work on the object. This work is negative
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