Page 136 - Plastics Engineering
P. 136

Mechanical Behaviour of Plastics                                119

               Therefore, using equation (2.75)




                                                     t      -0.1
                                          =    (2.4  x
                                   [E(t)l~* = 0.78t-'.'

                 The modulus at Tz(= 60°C) can now be calculated at any desired time. For
               example, at 1 year (t = 3.15 x  lo6 s)

                                   [E(t)]m = 0.78(3.15 x  lo6)-'.'
                                          = 0.14 GN/m2

                 The two modulus curves at 20°C and 60°C are illustrated in Fig. 2.61 along
               with the shift factor.


                       1
                     0.9
                     0.8

                     0.7
                   N
                   E
                   f 0.6
                   f  -  0.5
                   1 0.4
                   5
                     0.3
                     0.2
                     0.1

                      0
                       1


                      Fig. 2.61  Variation of modulus with time and temperature for polypropylene

               2.15  Fracture Behaviour of Unreinforced Plastics
               If  a  plastic  moulding  fails  in  the  performance of  its  normal  function  it  is
               usually caused by one of two factors - excessive deformation or fracture. In the
               previous sections it was pointed out that, for plastics, more often than not it will
               be excessive creep deformation which is the limiting factor. However, fracture,
   131   132   133   134   135   136   137   138   139   140   141