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                                                            Power electronic control in electrical systems 375

                         9.2   A basic worked example ± leading and lagging loads

                      Figure 9.1 shows a circuit with a supply system whose open-circuit voltage is E and
                      short-circuit impedance is Z s ˆ 0 ‡ jX s , where X s ˆ 0:1 
. The load impedance is
                      Z ˆ 1 
 but the power factor can be unity, 0.8 lagging, or 0.8 leading. For each of
                      these three cases, the supply voltage E must be adjusted to keep the terminal voltage
                      V ˆ 100 V. For each case determine E, the power-factor angle f, the load angle d, the
                      power P, the reactive power Q, and the volt-amperes S.












                      Fig. 9.1 Simple AC circuit.


                      Unity power-factor. Referring to Figure 9.2, we have E cos d ˆ V ˆ 100 and E sin d ˆ
                      X s I ˆ 0:1   100/1 ˆ 10 V. Therefore E ˆ 100 ‡ j10 ˆ 100:5e j5:71    V. The power-factor
                                                                                   j0
                      angleisf ˆ cos  1  (1) ˆ 0,d ˆ 5:71 ,andS ˆ P ‡ jQ ˆ VI ˆ 100   100e ˆ 10 kVA,


                      with P ˆ 10 kW and Q ˆ 0.








                      Fig. 9.2 Unity PF.


                      Lagging power-factor. Referring to Figure 9.3, the current is rotated negatively to a
                      phase angle of f ˆ cos  1  (0:8) ˆ 36:87 . Although I ˆ 100 A and X s I is still 10 V,

                      its new orientation `stretches'the phasor E to a larger magnitude: E ˆ V ‡ jX s I ˆ














                      Fig. 9.3 Lagging PF.
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