Page 130 - Probability Demystified
P. 130

CHAPTER 7 The Binomial Distribution                                         119

                     EXAMPLE: An archer hits the bull’s eye 80% of the time. If he shoots
                     5 arrows, find the probability that he will get 4 bull’s eyes.

                     SOLUTION:

                          n ¼ 5, x ¼ 4, p ¼ 0.8, 1   p ¼ 1   0.8 ¼ 0.2

                                                  4    1
                          Pð4 bull’s eyesÞ¼ C ð0:8Þ ð0:2Þ
                                           5
                                             4
                                        ¼ 5   0:08192
                                        ¼ 0:4096
                        In order to construct a probability distribution, the following formula
                     is used:
                              x
                          n C x p (1   p) n   x  where x ¼ 1, 2, 3, .. . n.
                     The next example shows how to use the formula.

                     EXAMPLE: A die is rolled 3 times. Construct a probability distribution for
                     the number of fives that will occur.


                     SOLUTION:
                     In this case, the die is tossed 3 times, so n ¼ 3. The probability of getting a 5
                                1
                     on a die is , and one can get x ¼ 0, 1, 2, or 3 fives.
                                6
                                             3
                                         0
                                       1   5
                        For x ¼ 0, C 0        ¼ 0:5787
                                  3
                                       6
                                           6
                                             2
                                         1
                                       1   5
                        For x ¼ 1, C 1        ¼ 0:3472
                                  3
                                       6   6
                                             1
                                         2
                                       1   5
                        For x ¼ 2, C 2  6  6  ¼ 0:0694
                                  3
                                             0
                                         3
                                       1   5
                        For x ¼ 3, C 3        ¼ 0:0046
                                  3
                                       6   6
                        Hence, the probability distribution is
                                   Number of fives, x  0      1       2      3
                                   Probability, P(x)  0.5787  0.3472  0.0694  0.0046
   125   126   127   128   129   130   131   132   133   134   135