Page 212 - Probability Demystified
P. 212
CHAPTER 11 Game Theory 201
Let s ¼ the probability of Player B hiding behind a rock and
1 s ¼ the probability of hiding in a tree; then
0:5s þ 0:2ð1 sÞ¼ 0:3s þ 0:8ð1 sÞ
0:5s þ 0:2 0:2s ¼ 0:3s þ 0:8 0:8s
0:3s þ 0:2 ¼ 0:5s þ 0:8
0:3s þ 0:5s þ 0:2 ¼ 0:5s þ 0:5s þ 0:8
0:8s þ 0:2 ¼ 0:8
0:8s þ 0:2 0:2 ¼ 0:8 0:2
0:8s ¼ 0:6
0:8s 0:6
¼
0:8 0:8
3
s ¼
4
Hence, player B should hide behind the rock 3 times out of 4.
3. The payoff table is
Player B
Player A Two Four
Ace 3 5
Three 5 7
