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3. Multivariate Random Variables  175

                              3.9.8 First show that f(x) = x  for x ∈ ℜ  is a convex function. Next,
                                                       –1
                                                                  +
                           suppose that X is a real valued random variable such that P(X > 0) = 1 and
                           E[X] is finite. Show that
                              (i)  E[1/X] > 1/E[X];
                              (ii) Cov(X, 1/X) < 0.
                              3.9.9 Suppose that X and Y are two random variables with finite second
                           moments. Also, assume that P(X + Y = 0) < 1. Show that



                           {Hint: Observe that (X + Y)  ≥ |X|{|X + Y|} + |Y|{|X + Y|}. Take expectations
                                                  2
                           throughout and then apply the Cauchy-Schwarz inequality on the rhs.}
                              3.9.10 Suppose that X , ..., X  are arbitrary random variables, each with
                                                       n
                                                 1
                           zero mean and unit standard deviation. For arbitrary ε(> 1), show that


                           {Hint: Let A  be the event that     , i = 1, ..., n. By Tchebysheff’s
                                      i
                                                 2 –1
                           inequality, P(A ) ≥ 1 – (nε ) , i = 1, ..., n. Then apply Bonferroni inequality,
                                       i
                                                                                         –2
                           namely,                             ≥ n{1 – (nε ) } – (n–1) = 1 – ε .}
                                                                        2 –1
                              3.9.11 Suppose that Y is a random variable for which E[Y] = 3 and E[Y ]
                                                                                          2
                           = 13. Show that P{–2 < Y < 8} > 21/25. {Hint: Check that V[Y] = 4 so that
                           P{–2 < Y < 8} = P{|Y – 3| < 5} > 1 – 4/25 = 21/25, by Tchebysheff’s
                           inequality.}
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