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252    5. Concepts of Stochastic Convergence

                                 The variance of each term in (5.2.20) would be equal to
                                                                              , since (i) we pretend
                                 that µ = 0, and (ii) the X’s are assumed independent. Also, the covariances
                                 such as


                                 and hence from (5.2.20) we get




                                 See (1.6.11) for the sum of successive positive integers. Next, by taking each
                                 covariance term into consideration, similarly one has



                                 Now combining (5.2.17)-(5.2.22), we obtain



                                 so that one writes


                                 Now, obviously           as n → ∞. Using the Theorem 5.2.2 with r = 2
                                 and a = σ , it follows that     as n → ∞. By applying the Theorem
                                          2
                                 5.2.5, we can also conclude, for example, that    as n → ∞ or
                                 as n → ∞.
                                    Remark 5.2.2 If the X’s considered in the Example 5.2.11 were assumed
                                 iid N(µ,σ ), then we would have had µ  = 3σ  so that (5.2.23) would reduce to
                                                                      4
                                         2
                                                                 4
                                 Note that (5.2.24) is also directly verified by observing that    is distributed
                                 as                so that one can write
                                                                                .

                                 Example 5.2.12 (Example 5.2.11 Continued) Let us continue working under
                                 the non-normal case and define              where 0 < γ < 1. Now, by
                                 the Markov inequality and (5.2.23), with k  = µ  – (n – 3)(n – 1) σ  and for
                                                                                        –1
                                                                                          4
                                                                         4
                                                                     n
                                 any fixed ε(> 0), we can write:
                                 Hence, by the Definition 5.2.1,    as n → ∞, whenever µ  is finite and
                                                                                      4
                                       4
                                 µ  > σ . !
                                  4
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