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348    7. Point Estimation

                                 The matrix G would be n.d. if and only if its odd order principal minors are
                                 negative and all even order principal minors are positive. Refer to (4.8.6) as
                                 needed. In this case, the first diagonal is -nu  which is negative and det(G) =
                                                                      -1
                                                                                              2
                                    2 -3
                                 ½n u  which is positive. In other words, G is a n.d. matrix. Thus, L(µ, s ) is
                                                                                           2
                                 globally maximized at              That is, the MLE of µ and σ  are re-
                                 spectively      and                      !
                                    Next we include few examples to highlight the point that L(θ) may not be
                                 a differentiable function of θ where L(θ) attains the global maximum. In such
                                 situations, the process of finding the MLE turns out little different on a case
                                 by case basis.


















                                    Example 7.2.88 88 8 Suppose that we have a single observation X which is
                                 distributed as Bernoulli(p) where 0 ≤ p ≤ 1 is the unknown parameter. Here,
                                 we have



                                 Whether we observe x = 0 or 1, the resulting likelihood function L(p) is not
                                 differentiable at the end points. But, by simply drawing a picture of L(p) one
                                 can verify that (i) when x = 0 then L(p) is maximized if p is the smallest, that
                                 is if p = 0, and (ii) when x = 1 then L(p) is maximized if p is the largest, that
                                 is if p = 1. Hence the MLE of p is    when Θ = [0, 1].
                                    But, if the parameter space happens to be Θ = [1/3, 2/3] instead, then
                                 what will be the MLE of p? Again, L(p) is maximized at the end points
                                 where L(p) is not differentiable. By examining the simple picture of L(p)
                                 in the Figure 7.2.2, it becomes clear in this situation that (i) when x = 0,
                                 L(p) is maximized if p is the smallest, that is if p = 1/3, and (ii) when x =
                                 1, L(p) is maximized if p is the largest, that is if p = 2/3. Hence the MLE of
                                 p is             if the parameter space happens to be Θ = [1/3, 2/3]. !
                                    Example 7.2.9 Suppose that X , ..., X  are iid Uniform(0, θ) where 0
                                                               1      n
                                                                        χ
                                 < θ <  ∞ is the unknown parameter. Here   = (0,  θ) and  Θ =  ℜ . We
                                                                                             +
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