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376    7. Point Estimation

                                 statistic g(U) is the UMVUE for T(θθ θθ θ). Then, we have:



                                    Proof Since the statistic U is assumed both complete and sufficient, by
                                 virtue of the Lehmann-Scheffé Theorems it follows that E [T | U] must be the
                                                                                 θ
                                 best unbiased estimator of T(θθ θθ θ). But g(U) is the unique UMVUE of T(?) and
                                 hence the result follows immediately. !
                                    Example 7.5.15 Suppose that X , ..., X  are iid N(µ, σ ) where µ is un-
                                                                                   2
                                                               1     n
                                 known but σ  is known with n = 4, −∞ < µ < ∞, 0 < σ < ∞ and  χ  = ℜ. Let
                                            2
                                                  which is unbiased for  T(µ) = 2µ and U =     . But, U is
                                 complete sufficient for µ and hence g(U) = 2U is the unique UMVUE for T(µ).
                                 Thus, in view of the Theorem 7.5.5 we can immediately write E [T |     .2
                                                                                       µ
                                                             2
                                                                             2
                                                                                   2
                                 Instead if we had T = (X  + X ) , then E [T] = 4µ  + 2σ  =  T(µ). But, the
                                                       1
                                                                     µ
                                                            2
                                 unique UMVUE of µ  was earlier (Example 7.5.7) found to be
                                                   2
                                 Hence in view of the Theorem 7.5.5, we can immediately write
                                                                  !
                                       Suppose that X , ..., X  are random samples from Poisson(λ),
                                                          n
                                                    1
                                       0 < λ < ∞. Among other things, the following example shows
                                                   easily that V (S ) > V      for all λ.
                                                                2
                                                             λ
                                                                     λ
                                    Example 7.5.16 Suppose that X , ..., X  are iid Poisson(λ) with 0 < λ < ∞
                                                               1    n
                                 unknown and n ≥ 2. Let us denote T = S , the sample variance, and U =
                                                                    2
                                 Obviously, E [T] = λ =  T(λ). But, U is complete sufficient and so U is the
                                            λ
                                 unique UMVUE for T(λ). Thus, in view of the Theorem 7.5.5, we can write
                                 E [T |     ] =    .
                                  λ
                                                                                    2
                                    Now, we use the Theorem 3.3.1, part (ii) to rewrite V (S ) as
                                                                                  θ
                                 which exceeds V [ ] , for all λ, because V(S  | ) is a positive random
                                                                          2
                                                λ
                                 variable whose expectation is positive. For the direct calculation of V (S ),
                                                                                                2
                                                                                             θ
                                 however, refer to the expression given by (5.2.23). !
                                    Example 7.5.17 Let X , ..., X  be iid Uniform (0, θ) where θ(> 0) is the
                                                             n
                                                       1
                                 unknown parameter with n ≥ 2. Then, U = X  is complete sufficient for θ.
                                                                        n:n
                                 Consider             Obviously, E [T] = ½θ+1/3θ  = T (θ). Now, since U
                                                                              2
                                                                 θ
                                                                                            -1
                                                     n-1 -n
                                 has its pdf given by nu θ I (0 < u < θ), we have E [X ] = n(n+1) θ and
                                                                              θ  n:n
                                                         Hence, the unique UMVUE of  T(θ) is given by
                                                                  Thus, in view of the Theorem 7.5.5,
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