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11. Likehood Ratio and Other Tests  529

                           the lines of (11.4.13), we can propose the following lower-sided level α test.





                              Two-Sided Alternative Hypothesis

                              We test H  : σ  = σ  versus H  : σ  ≠ σ . See the Figure 11.4.4. Along the
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                                                              2
                                          1
                                      0
                                                      1
                                              2
                           lines of (11.4.11), we can propose the following two-sided level α test.
                              Example 11.4.3 (Example 11.4.1 Continued) Consider that data on (X ,
                                                                                          1
                           X ) from the Example 11.4.1 for the 8 employees on their job performance
                            2
                           scores before and after the training. Assuming the bivariate normal distribu-
                           tion for (X , X ), we may like to test whether the job performance scores after
                                   1
                                      2
                           the training are less variable than those taken before the training. At the 1%
                           level, we may want to test H  : σ  = σ  versus H  : σ  > σ  or equivalently test
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                                                   0
                                                                          2
                                                                      1
                                                          2
                                                                   1
                           H  : ρ* = 0 versus H  : ρ* > 0 where ρ* is the population correlation coeffi-
                            0               1
                           cient between Y , Y . For the observed data, one has
                                        1  2
                                            Y        Y                 Y        Y
                                             1        2                 1        2
                                  ID #    X  + X   X  – X    ID #    X + X    X  – X
                                           1   2    1   2             1   2    1    2
                                   1       150      –10        5       183      –5
                                   2       168       2         6       164      –8
                                   3       142       –8        7       132      –6
                                   4       154       –6        8       160       4
                           One should check that the sample correlation coefficient between Y , Y  is r*
                                                                                    1
                                                                                      2
                           = .34641. From (11.4.15), we find the observed value of the test statistic:
                           With α = .01 and 6 degrees of freedom, one has t 6,.01  = 3.1427. Since t  does
                                                                                     calc
                           not exceed t 6,.01 , we do not reject the null hypothesis at 1% level and conclude
                           that the variabilities in the job performance scores before and after the training
                           appear to be same. !

                           11.5 Exercises and Complements

                              11.2.1 Verify the result given in (11.2.4).
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