Page 348 - Schaum's Outline of Theory and Problems of Advanced Calculus
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CHAP. 13]                         FOURIER SERIES                                339


                     DIFFERENTIATION AND INTEGRATION OF FOURIER SERIES
                        Differentiation and integration of Fourier series can be justified by using the theorems on Pages 271
                     and 272, which hold for series in general. It must be emphasized, however, that those theorems provide
                     sufficient conditions and are not necessary. The following theorem for integration is especially useful.

                     Theorem.  The Fourier series corresponding to f ðxÞ may be integrated term by term from a to x, and the
                                                         ð  x
                     resulting series will converge uniformly to  f ðxÞ dx provided that f ðxÞ is piecewise continuous in
                                                          a
                      L @ x @ L and both a and x are in this interval.


                     COMPLEX NOTATION FOR FOURIER SERIES
                        Using Euler’s identities,
                                              i
                                             e ¼ cos   þ i sin  ;  e  i   ¼ cos     i sin            ð6Þ
                             p ffiffiffiffiffiffiffi
                                1 (see Problem 11.48, Chapter 11, Page 295), the Fourier series for f ðxÞ can be written as
                     where i ¼
                                                             1
                                                            X      in x=L
                                                                c n e
                                                      f ðxÞ¼                                         ð7Þ
                                                            n¼ 1
                     where
                                                        1  ð L    in x=L
                                                             f ðxÞe    dx
                                                    c n ¼                                            ð8Þ
                                                        2L  L
                        In writing the equality (7), we are supposing that the Dirichlet conditions are satisfied and further
                     that f ðxÞ is continuous at x.  If f ðxÞ is discontinuous at x, the left side of (7)should be replaced by
                                     :
                     ðf ðx þ 0Þþ f ðx   0Þ
                            2

                     BOUNDARY-VALUE PROBLEMS
                        Boundary-value problems seek to determine solutions of partial differential equations satisfying
                     certain prescribed conditions called boundary conditions.  Some of these problems can be solved by
                     use of Fourier series (see Problem 13.24).

                     EXAMPLE.  The classical problem of a vibrating string may be idealized in the following way. See Fig. 13-2.
                        Suppose a string is tautly stretched between points ð0; 0Þ and ðL; 0Þ. Suppose the tension, F,is the
                     same at every point of the string.  The string is made to
                     vibrate in the xy plane by pulling it to the parabolic
                                          2
                     position gðxÞ¼ mðLx   x Þ and releasing it.  (m is a
                     numerically small positive constant.)  Its equation will
                     be of the form y ¼ f ðx; tÞ.  The problem of establishing
                     this equation is idealized by (a) assuming that the con-
                     stant tension, F,isso large as compared to the weight wL
                     of the string that the gravitational force can be neglected,
                     (b) the displacement at any point of the string is so small
                     that the length of the string may be taken as L for any of
                     its positions, and (c) the vibrations are purely transverse.
                                                                2
                                                          w    @ y
                     The force acting on a segment PQ is     x    ;
                                                           g   @t 2
                                                 2
                     x < x 1 < x þ  x; g   32 ft per sec: .  If   and   are the
                     angles that F makes with the horizontal, then the vertical    Fig. 13-2
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