Page 412 - Schaum's Outline of Theory and Problems of Applied Physics
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CHAP. 32]                                 LENSES                                      397



        SOLVED PROBLEM 32.2
              A meniscus lens has one concave and one convex surface. The concave surface of a particular meniscus
              lens has a radius of curvature of 30 cm, and its convex surface has a radius of curvature of 50 cm. The
              index of refraction of the glass used is 1.50. (a) Find the focal length of the lens. (b) Is it a converging
              lens or a diverging lens?
              (a) Here R 1 =−30 cm (since the first surface is concave, its radius is considered negative), and R 2 =+50 cm.
                  Hence
                           1            1  1                   1      1                −1
                             = (n − 1)   +     = (1.50 − 1.00) −   +       =−0.00667 cm
                           f          R 1  R 2                30 cm  50 cm
                                     1
                           f =−            =−150 cm
                                 0.00667 cm −1
              (b) A negative focal length signifies a diverging lens.

        SOLVED PROBLEM 32.3
              A lens made of glass whose index of refraction is 1.60 has a focal length of +20 cm in air. Find its focal
              length in water, whose index of refraction is 1.33.
                  Let f be the focal length of the lens in air and f be its focal length in water. The index of refraction of the

              glass relative to air is n = 1.60 since the index of refraction of air is very nearly equal to 1. The index of refraction
              of the glass relative to water is
                                          index of refraction of glass  1.60

                                      n =                     =     = 1.20
                                          index of refraction of water  1.33
              From the lensmaker’s equation, since R 1 and R 2 are the same in both air and water,
                                            f     n − 1  1.60 − 1.00
                                              =       =          = 3
                                            f   n − 1   1.20 − 1.00

              and so                       f = 3 f = (3)(+20 cm) =+60 cm

              The focal length of any lens made of this glass is three times longer in water than in air.


        SOLVED PROBLEM 32.4
              Both surfaces of a double-concave lens whose focal length is −9 cm/cm have a radii of 10 in. Find the
              index of refraction of the glass.
                  From the lensmaker’s equation
                                         1                     1
                            n − 1 =             =                             = 0.56
                                   f (1/R 1 + 1/R 2 )  (−9cm)[1/(−10 cm) + 1/(−10 cm)]
                               n = 0.56 + 1 = 1.56

        SOLVED PROBLEM 32.5

              The focal length f of a combination of two thin lenses in contact whose individual focal lengths are f 1
              and f 2 is given by
                                               1    1    1
                                                 =    +
                                               f    f 1  f 2
              Use this formula to find the focal length of a combination of a converging lens of f =+10 cm and a
              diverging lens of f =−20 cm that are in contact.
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