Page 415 - Schaum's Outline of Theory and Problems of Applied Physics
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400                                      LENSES                                  [CHAP. 32



                                                 Table 32-1

                                   Quantity        Positive     Negative

                                Focal length f   Concave lens  Diverging lens
                                Object distance p  Real object  Virtual object
                                Image distance q  Real image  Virtual image
                                Magnification m   Erect image  Inverted image
                                Height h         Erect image  Inverted image



        SOLVED PROBLEM 32.8
              A coin 3 cm in diameter is placed 24 cm from a converging lens whose focal length is 16 cm. Find the
              location, size, and nature of the image.

                  Here p = 24 cm and f =+16 cm, so the image distance is
                                              pf    (24 cm)(16 cm)
                                         q =      =             = 48 cm
                                             p − f  24 cm − 16 cm

              The image is real since q is positive (Fig. 32-6). Since m = h /h =−q/p, the diameter of the coin’s image is
                                              q            48 cm

                                        h =−h   =−(3cm)          =−6cm
                                               p          24 cm

              The image is inverted (since h is negative) and twice as large as the object.
                  In general, an object that is a distance between f and 2 f from a converging lens has a real, inverted image that
              is larger than the object.

                                                             F′      2F′
                                    2F      F


                                                    Fig. 32-6


        SOLVED PROBLEM 32.9
              A sardine 8 cm long is 30 cm from a converging lens whose focal length is 15 cm. Find the location, size,
              and nature of the image.

                  Here p = 30 cm and f =+15 cm, so the image distance is
                                              pf    (30 cm)(15 cm)
                                         q =      =             = 30 cm
                                             p − f  30 cm − 15 cm
              The image is real since q is positive (Fig. 32-7). The length of the sardine’s image is
                                              q            30 cm
                                        h =−h   =−(8cm)          =−8cm

                                               p          30 cm

              The image is inverted (since h is negative) and is the same size as the object.

                                            F′      2F′                                F′     2F′
                    2F      F                                  2F      F

                                 Fig. 32-7                                Fig. 32-8
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