Page 462 - Schaum's Outline of Theory and Problems of Applied Physics
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CHAP. 36]                            NUCLEAR PHYSICS                                  447



        HALF-LIFE
        A nucleus subject to radioactive decay always has a certain definite probability of decay during any time interval.
        The half-life of a radioactive isotope is the time required for half of any initial quantity to decay. If an isotope
        has a half-life of, say 5 h, and we start with 100 g of it, 50 g will be left undecayed after 5 h; 25 g will be left
        undecayed after 10 h; 12.5 g will be left undecayed after 15 h; and so on.

        SOLVED PROBLEM 36.12
                                        3
              Tritium is the hydrogen isotope H whose nucleus contains two neutrons and a proton. Tritium is beta-
                                        1
              radioactive and emits an electron. (a) What does tritium become after beta decay? (b) The half-life of
              tritium is 12.5 yr. How much of a 1-g sample will remain undecayed after 25 yr?
              (a) In the beta decay of a nucleus, one of its neutrons becomes a proton. Since the atomic number 2 corresponds
                                       3
                  to helium, the beta decay of Hisgiven by
                                       1
                                                        3
                                                   3 H → He + e −
                                                   1    2
                                 3
                  and the new atom is He.
                                 2
              (b) Twenty-five years is two half-lives of tritium, and so  1  ×  1  × 1g =  1  g of tritium remains undecayed.
                                                        2   2       4
        SOLVED PROBLEM 36.13
                                          24
              The half-life of the sodium isotope Na against beta decay is 15 h. How long does it take for seven-eighths
                                          11
              of a sample of this isotope to decay?
                  After seven-eighths has decayed, one-eighth is left, and  1  =  1  ×  1  ×  1  which is three half-lives. Hence the
                                                           8   2  2   2
              answer is (3)(15) h = 45 h.

        SOLVED PROBLEM 36.14
                              14
              The carbon isotope C (called radiocarbon) is beta-radioactive with a half-life of 5600 yr. Radiocarbon
                               6
              is produced in the earth’s atmosphere by the action of cosmic rays on nitrogen atoms, and the carbon
              dioxide of the atmosphere contains a small proportion of radiocarbon as a result. All plants and animals
                                                                             12
              therefore contain a certain amount of radiocarbon along with the stable isotope C. When a living thing
                                                                              6
              dies, it stops taking in radiocarbon and the radiocarbon it already contains decays steadily. By measuring
              the ratio between the  14 C and  12 C contents of the remains of an animal or plant and comparing it with
                                6      6
              the ratio of these isotopes in living organisms, the time that has passed since the death of the animal or
              plant can be found. (a) How old is a piece of wood from an ancient dwelling if its relative radiocarbon
              content is one-fourth that of a modern specimen? (b) If it is one-sixteenth that of a modern specimen?
                              1
              (a) Since  1  =  1  × , the specimen is two half-lives old, which is 11,200 yr old.
                       4  2   2
                                     1
              (b) Since  1  =  1  ×  1  ×  1  × , the specimen is four half-lives old, which is 22,400 yr old.
                       16  2  2   2  2
        SOLVED PROBLEM 36.15
              The rate at which a sample of radioactive substance decays is called its activity. A unit of activity is the
              curie (Ci), where 1 curie = 3.7 × 10 10  decays/s. If a luminous watch dial contains 5 µCi of the radium
              isotope  226 Ra, how many decays per second occur in it? (This isotope emits alpha particles which cause
                     88
              flashes of light when they strike a special material the isotope is mixed with.)
                  Since 1 µCi is 10 −6  Ci, the activity of the watch dial is

                                           decays/s
                                                                      5
                                   3.7 × 10 10     (5 × 10 −6  Ci) = 1.85 × 10 decays/s
                                             Ci
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