Page 457 - Schaum's Outline of Theory and Problems of Applied Physics
P. 457

442                                 NUCLEAR PHYSICS                              [CHAP. 36



                                  Table 36-1. The Four Fundamental Interactions

                Interaction      Range       Relative Strength        Role in Universe

              Strong         Approx. 10 −15  m     1         Holds protons and neutrons together to
                                                              form atomic nuclei.
              Electromagnetic  Infinite         Approx. 10 −2  Determines structures of atoms,
                                                              molecules, solids, and liquids; is an
                                                              important factor in the astronomical
                                                              universe.
              Weak           Approx. 10 −17  m  Approx. 10 −13  Helps determine compositions of atomic
                                                              nuclei.
              Gravitational  Infinite          Approx. 10 −40  Assembles matter into planets, stars, and
                                                              galaxies.



        SOLVED PROBLEM 36.2
              State the number of protons and neutrons in the following nuclei:
                                        6      12     36    137
                                        3 Li   6 C    16 S   56  Ba
                                  A
                  A nucleus designated X contains Z protons and A − Z neutrons. Accordingly, the numbers of protons and
                                  Z
              neutrons in the given nuclei are as follows:
                                            6 Li :   3 protons, 3 neutrons
                                            3
                                            12 C :   6 protons, 6 neutrons
                                            6
                                            36 S :  16 protons, 20 neutrons
                                            16
                                          137 Ba :  56 protons, 81 neutrons
                                           56

        SOLVED PROBLEM 36.3
                                                         35
                                                                                       37
              Ordinary chlorine is a mixture of 75.53 percent of the Cl isotope and 24.47 percent of the Cl isotope.
                                                         17                            17
              The atomic masses of these isotopes are, respectively, 34.969 and 36.966 u. Find the average atomic mass
              of ordinary chlorine.
                  The procedure is to multiply the mass of each isotope by the proportion of the whole it represents and then to
              add the results. Thus we obtain
                                    (0.7553)(34.969 u) + (0.2447)(36.966 u) = 35.458 u

              which is the average atomic mass of ordinary chlorine quoted in chemical tables.





        BINDING ENERGY
        The mass of an atom is always less than the sum of the masses of the neutrons, protons, and electrons of which it
        is composed. The energy equivalent of the missing mass is called the binding energy of the nucleus; the greater
        its binding energy, the more stable the nucleus. The mass defect  m of a nucleus with Z protons and N neutrons
        may be found from its atomic mass m by using the formula

                                           m = Zm H + Nm n − m
   452   453   454   455   456   457   458   459   460   461   462