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146 LAPLACE TRANSFORM AND CONTINUOUS-TIME LTI SYSTEMS [CHAP. 3
3.27. Using the Laplace transfer, redo Prob. 2.14.
(a) Using Eqs. (3.36) and (3.40, we have
Y(s) =X(s)H,(s)H,(s) =X(s)H(s)
where H(s) = H,(s)H,(s) is the system function of the overall system. Now from Table
3-1 we have
Hence,
Taking the inverse Laplace transfer of H(s), we get
h(t) = 2(ep' - e-2')u(t)
(b) Since the ROC of H(s), Re(s) > - 1, contains the jo-axis, the overall system is stable.
3.28. Using the Laplace transform, redo Prob. 2.23.
The system is described by
Taking the Laplace transform of the above equation, we obtain
sY(s) + aY(s) = X(s) or (s + a)Y(s) = X(s)
Hence, the system function H(s) is
Assuming the system is causal and taking the inverse Laplace transform of H(s), the impulse
response h(t ) is
h(t) = e-"'u(t)
which is the same as Eq. (2.124).
3.29. Using the Laplace transform, redo Prob. 2.25.
The system is described by
yf(t) + 2y(t) =x(t) +xl(t)
Taking the Laplace transform of the above equation, we get
sY(s) + 2Y(s) = X(s) + sX(s)
or (s + 2)Y(s) = (s + l)X(s)