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146         LAPLACE TRANSFORM AND CONTINUOUS-TIME LTI SYSTEMS                  [CHAP.  3



            3.27.  Using the Laplace transfer, redo Prob. 2.14.

                  (a)  Using Eqs. (3.36) and (3.40, we  have
                                            Y(s) =X(s)H,(s)H,(s) =X(s)H(s)
                      where  H(s) = H,(s)H,(s) is  the system function of  the overall system. Now  from Table
                      3-1 we  have








                      Hence,




                      Taking the inverse Laplace transfer of  H(s), we  get
                                                  h(t) = 2(ep' - e-2')u(t)

                 (b)  Since the ROC of H(s), Re(s) > - 1, contains the jo-axis, the overall system is stable.


           3.28.  Using the Laplace transform, redo Prob. 2.23.
                     The system is described by




                 Taking the Laplace transform of  the above equation, we obtain

                                   sY(s) + aY(s) = X(s)    or    (s + a)Y(s) = X(s)
                 Hence, the system function  H(s) is




                 Assuming the system  is causal and taking the  inverse Laplace transform of  H(s), the  impulse
                 response h(t ) is
                                                    h(t) = e-"'u(t)
                 which is the same as Eq. (2.124).


           3.29.  Using the Laplace transform, redo Prob. 2.25.

                     The system is described by
                                              yf(t) + 2y(t) =x(t) +xl(t)
                 Taking the Laplace transform of  the above equation, we  get
                                             sY(s) + 2Y(s) = X(s) + sX(s)

                 or                           (s + 2)Y(s) = (s + l)X(s)
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