Page 156 - Schaum's Outlines - Probability, Random Variables And Random Processes
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CHAP. 41  FUNCTIONS  OF RANDOM  VARIABLES, EXPECTATION,  LIMIT  THEOREMS          149



          4.41.  Verify Eq. (4.36).

                   Since X and Y are independent, we have











               The proof for the discrete case is similar


          4.42.  Let X and Y be defined by
                                           X = cos 0      Y = sin O
               where O is a random variable uniformly distributed over (0, 271).

               (a)  Show that X and Y are uncorrelated.
               (b)  Show that X and Y are not independent.

               (a)  We have
                                                     P


                                                     (0    otherwise
                   Then          E(X) = I:m~fx(x)  di = l* cos Ofe(0) d0 =



                   Similarly,                 E(Y)=~  $  sin 0 d0=0
                                                         ax px
                                       1
                                E(XY) = i;   cos 0 sin 0 d0 = -  sin 20 d0 = 0 = E(X)E(Y)
                   Thus, by Eq. (3.52), X and Y are uncorrelated.



                                        1             1                 1
                                                                        2
                                             sin2
                                 E(Y2) = Z; In 0 d0 =   ['(I   - cos 20) d0 = -
                                                                              1
                                                              (
                                                                              8
                               E(x'Y')   = & % cos2 0 sin2 0 10 = -  1  - cos 4,  d0 = -
                   Hence
                   If  X and Y were independent, then by Eq. (4.36), we would have E(X2Y2) = E(X2)E(Y2). Therefore, X
                   and Y are not independent.


          4.43.  Let XI, . . . , Xn be n r.v.3. Show that
                                                     n   n
                                      Var  xaiXi  = x  xaiajCov(Xi, Xj)
                                         (i11  )  i=1 j=1
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